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482<br />

Part Three<br />

Planning and control<br />

Figure 16.20 Probabilistic time estimates can be summed to give a probabilistic estimate for<br />

the whole project<br />

The variance of the distribution (V) can be calculated as follows:<br />

(t (t p − t o ) 2<br />

p − t o ) 2<br />

V = =<br />

6 2 36<br />

The time distribution of any path through a network will have a mean which is the sum of<br />

the means of the activities that make up the path, and a variance which is a sum of their variances.<br />

In Figure 16.21:<br />

2 + (4 × 3) +5<br />

The mean of the first activity = = 3.17<br />

6<br />

(5 − 2) 2<br />

The variance of the first activity = = 0.25<br />

36<br />

3 + (4 × 4) +7<br />

The mean of the second activity = = 4.33<br />

6<br />

(7 − 3) 2<br />

The variance of the second activity = = 0.44<br />

36<br />

The mean of the network distribution = 3.17 + 4.33 = 7.5<br />

The variance of the network distribution = 0.25 + 0.44 = 0.69<br />

It is generally assumed that the whole path will be normally distributed.<br />

The advantage of this extra information is that we can examine the ‘riskiness’ of each path<br />

through a network as well as its duration. For example, Figure 16.21 shows a simple two-path<br />

network. The top path is the critical one; the distribution of its duration is 10.5 with a variance<br />

of 0.06 (therefore a standard deviation of 0.245). The distribution of the non-critical<br />

path has a mean of 9.67 and a variance of 0.66 (therefore a standard deviation of 0.812). The

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