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Grassmann Algebra

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GeometricInterpretations.nb 31<br />

L � �� � ae1 � be2���� � ce2 � de3�;<br />

���� � ee1���� � fe2���� � ge3�;<br />

Next, take the regressive product of the line and the plane and simplify it.<br />

��L � ��<br />

� � e1 � e2 � e3 ���def� �b e� ce� af� g� � � ae�d f� �c � f� g� e1 �<br />

f �b e�d � g� � c ��a � e� g� e2 � d �be� �a � e� f� ge3�<br />

This shows that the intersection point P is given by:<br />

ae�d f� �c � f� g�<br />

P � � � �������������������������������� �������������������������<br />

def� �be� ce� af�g e1 �<br />

f �b e�d � g� � c ��a � e� g� d �b e� �a � e� f� g<br />

�������������������������������� ����������������������������������� e2 � �������������������������������� �������������������������<br />

def� �b e� ce� af�g def� �b e� ce� af�g e3;<br />

To verify that this point lies in both the line and the plane, we can take its exterior product with<br />

each of the lines and show the result to be zero.<br />

���L � P, � � P��<br />

�0, 0�<br />

In the special case in which the line is parallel to the plane, their intersection is no longer a<br />

point, but a vector defining their common direction. When the line lies in the plane, the result<br />

from the calculation will be zero.<br />

� The intersection of two planes in a 3-plane<br />

Suppose we wish to find the line L of intersection of two planes �1 and �2 in a 3-plane.<br />

First declare the basis of the 3-plane, and then define the planes.<br />

�3<br />

��, e1, e2, e3�<br />

�1 � �� � ae1���� � be2���� � ce3�;<br />

�2 � �� � ee1���� � fe2���� � ge3�;<br />

Next, take the regressive product of the two lines and simplify it.<br />

���1 � �2�<br />

� � e1 � e2 � e3 �<br />

�� ��ae�c f� bg� e1 � bf��c e� ag� e2 � c �b e� af� ge3� � abe<br />

f ��c � g� e1 � e2 � ace�b � f� ge1 � e3 � bc��a � e� fge2 � e3�<br />

This shows that the line of intersection L is given by:<br />

2001 4 5

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