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Grassmann Algebra

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ExpTheGeneralizedProduct.nb 26<br />

Similarly the triple generalized sums of form B for grades of 0, 1 and 2 are<br />

Table��i, TripleGeneralizedSumB�i��x,y,z��, �i, 0, 2�� ��<br />

m k p<br />

TableForm<br />

0 x �<br />

m 0 ���y<br />

� z<br />

���<br />

�k<br />

0 p�<br />

1�k<br />

1 ��1�<br />

���x<br />

�<br />

�m<br />

0 � ��y � z<br />

���<br />

�k<br />

1 p�<br />

���<br />

1�m<br />

� ��1�<br />

���x<br />

�<br />

�<br />

�m<br />

1 ���y<br />

� z<br />

���<br />

�k<br />

0 p�<br />

���<br />

�<br />

2 � ���x<br />

�<br />

�m<br />

0 ���y<br />

� z<br />

���<br />

�k<br />

2 p�<br />

���<br />

2�k�m<br />

� ��1�<br />

���x<br />

�<br />

�<br />

�m<br />

1 ���y<br />

� z<br />

���<br />

�k<br />

1 p�<br />

���<br />

� x �<br />

� m 2 ���y<br />

� z<br />

���<br />

�k<br />

0 p�<br />

The triple generalized sum conjecture<br />

As we have shown above, a single triple generalized product is not in general associative. That<br />

is, the A form and the B form are not in general equal. However we conjecture that the triple<br />

generalized sum of form A is equal to the triple generalized sum of form B.<br />

n<br />

�<br />

Λ�0<br />

���1� sA � �<br />

�<br />

��x m ����� Λ �y k<br />

n<br />

�z � �<br />

n�Λ p<br />

Λ�0<br />

����<br />

����<br />

�<br />

���1�sB �xm ����� �<br />

Λ ���y�<br />

����<br />

�k<br />

n�Λ �z p<br />

���<br />

�<br />

10.27<br />

where sA � m Λ� 1 ���� Λ �Λ�1� � �m � k� �n �Λ�� 2 1 ���� �n �Λ� �n �Λ�1�<br />

2<br />

and sB � m Λ� 1 ���� Λ �Λ�1� � k �n �Λ�� 2 1 ���� �n �Λ� �n �Λ�1�.<br />

2<br />

If this conjecture can be shown to be true, then the associativity of the Clifford product of a<br />

general <strong>Grassmann</strong> expression can be straightforwardly proven using the definition of the<br />

Clifford product in terms of exterior and interior products (or, what is equivalent, in terms of<br />

generalized products). That is, the rules of Clifford algebra may be entirely determined by the<br />

axioms and theorems of the <strong>Grassmann</strong> algebra, making it unnecessary, and indeed potentially<br />

inconsistent, to introduce any special Clifford algebra axioms.<br />

� Exploring the triple generalized sum conjecture<br />

We can explore the triple generalized sum conjecture by converting the generalized products<br />

into scalar products.<br />

For example first we generate the triple generalized sums.<br />

2001 4 26<br />

A � TripleGeneralizedSumA�2��x,y,z� 3 2<br />

���x � y� � z� � �x � y� � z � �x � y� � z<br />

3 2 2 0 3 1 2 1 3 0 2 2

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