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Grassmann Algebra

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Exploring<strong>Grassmann</strong><strong>Algebra</strong>.nb 39<br />

� Powers of <strong>Grassmann</strong> numbers<br />

The computation of powers of <strong>Grassmann</strong> numbers has already been discussed in Section 9.5.<br />

We can also calculate powers of <strong>Grassmann</strong> numbers using the <strong>Grassmann</strong>Function<br />

operation. The syntax we will usually use is:<br />

<strong>Grassmann</strong>Function�X a �<br />

Ξ 0 a � ae1 Ξ 0 �1�a Ξ1 � ae2 Ξ 0 �1�a Ξ2 � ae3 Ξ 0 �1�a Ξ3 �<br />

a Ξ 0 �1�a Ξ4 e1 � e2 � a Ξ 0 �1�a Ξ5 e1 � e3 � a Ξ 0 �1�a Ξ6 e2 � e3 �<br />

�Ξ 0 �2�a ��a � a 2 � Ξ2 Ξ5 � ��a � a 2 ��Ξ3 Ξ4 �Ξ1 Ξ6�� � a Ξ 0 �1�a Ξ7�<br />

e1 � e2 � e3<br />

<strong>Grassmann</strong>Function�X �1 �<br />

1<br />

�������<br />

Ξ0<br />

� e1 Ξ1<br />

�������������<br />

Ξ2 0<br />

Ξ6 e2 � e3<br />

����������������������� 2 Ξ0 � e2 Ξ2<br />

�������������<br />

Ξ2 0<br />

� e3 Ξ3<br />

�������������<br />

Ξ2 0<br />

� Ξ4 e1 � e2<br />

�����������������������<br />

Ξ2 0<br />

� ���<br />

�<br />

�2 Ξ2 Ξ5 � 2 �Ξ3 Ξ4 �Ξ1 Ξ6�<br />

�������������������������������� 3�������������������������������<br />

Ξ0 � Ξ5 e1 � e3<br />

�����������������������<br />

Ξ2 �<br />

0<br />

�<br />

�<br />

� Ξ7<br />

������� �� 2<br />

e1 � e2 � e3<br />

Ξ0 But we can also use <strong>Grassmann</strong>Function��x a ,x�, X�,<br />

�# a &��X� ��<strong>Grassmann</strong>Function or <strong>Grassmann</strong>Power[X,a] to get the same result.<br />

� Exponential and logarithmic functions of <strong>Grassmann</strong> numbers<br />

Exponential functions<br />

Here is the exponential of a general <strong>Grassmann</strong> number in 3-space.<br />

expX � <strong>Grassmann</strong>Function�Exp�X��<br />

� Ξ0 �� Ξ0 e1 Ξ1 �� Ξ0 e2 Ξ2 �� Ξ0 e3 Ξ3 �� Ξ0 Ξ4 e1 � e2 �� Ξ0 Ξ5 e1 � e3 �<br />

� Ξ0 Ξ6 e2 � e3 �� Ξ0 �Ξ3 Ξ4 �Ξ2 Ξ5 �Ξ1 Ξ6 �Ξ7� e1 � e2 � e3<br />

Here is the exponential of its negative.<br />

expXn � <strong>Grassmann</strong>Function�Exp��X��<br />

� �Ξ0 �� �Ξ0 e1 Ξ1 �� �Ξ0 e2 Ξ2 �� �Ξ0 e3 Ξ3 �<br />

� �Ξ0 Ξ4 e1 � e2 �� �Ξ0 Ξ5 e1 � e3 �� �Ξ0 Ξ6 e2 � e3 �<br />

� �Ξ0 �Ξ3 Ξ4 �Ξ2 Ξ5 �Ξ1 Ξ6 �Ξ7� e1 � e2 � e3<br />

We verify that they are indeed inverses of one another.<br />

2001 4 5<br />

��expX � expXn� ��Simplify<br />

1

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