14.02.2013 Views

Grassmann Algebra

Grassmann Algebra

Grassmann Algebra

SHOW MORE
SHOW LESS

You also want an ePaper? Increase the reach of your titles

YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.

TheExteriorProduct.nb 12<br />

<strong>Grassmann</strong> algebras<br />

Under the foregoing axioms it may be directly shown that:<br />

1. � 0 is a field.<br />

2. The � m are linear spaces over � 0 .<br />

3. The direct sum of the � m is an algebra.<br />

This algebra is called a <strong>Grassmann</strong> algebra. Its elements are sums of elements from the �, thus<br />

m<br />

allowing closure over both addition and exterior multiplication. For example we can evaluate<br />

the following product to give another element of the algebra:<br />

���1 � 2�x � 3�x � y � 4�x � y � z���1 � 2�x � 3�x � y � 4�x � y � z��<br />

1 � 4x� 6x� y � 8x� y � z<br />

A <strong>Grassmann</strong> algebra is also a linear space of dimension 2n , where n is the dimension of the<br />

underlying linear space �. We will refer to a <strong>Grassmann</strong> algebra whose underlying linear space<br />

1<br />

is of dimension n as an n-algebra.<br />

<strong>Grassmann</strong> algebras will be discussed further in Chapter 9.<br />

On the nature of scalar multiplication<br />

The anti-commutativity axiom �10 for general elements states that:<br />

Α m � Β k<br />

� ��1� mk  k<br />

� Α m<br />

If one of these factors is a scalar (Β k<br />

Α m � a � a � Α m<br />

� a, say; k = 0), the axiom reduces to:<br />

Since by axiom �6, each of these terms is an m-element, we may permit the exterior product to<br />

subsume the normal field multiplication. Thus, if a is a scalar, a � Α is equivalent to a�Α. The<br />

m m<br />

latter (conventional) notation will usually be adopted.<br />

In the usual definitions of linear spaces no discussion is given to the nature of the product of a<br />

scalar and an element of the space. A notation is usually adopted (that is, the omission of the<br />

product sign) that leads one to suppose this product to be of the same nature as that between two<br />

scalars. From the axioms above it may be seen that both the product of two scalars and the<br />

product of a scalar and an element of the linear space may be interpreted as exterior products.<br />

2001 4 5<br />

a � Α m � Α m � a � a�Α m<br />

a �� 0<br />

2.20

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!