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Grassmann Algebra

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TheRegressiveProduct.nb 4<br />

The grade of the space to which the regressive product belongs is nÐ(m+k) = nÐ((nÐm')+(nÐk'))<br />

= (m'+k')Ðn.<br />

Finally, since the primes are no longer necessary we drop them. Then the final form of the<br />

axiom dual to �6, which we label �6, becomes:<br />

�Α m �� m , Β k<br />

�� k � � Α m � Β k<br />

� �<br />

m�k�n<br />

In words, this says that the regressive product of an m-element and a k-element is an (m+kÐn)element.<br />

The dual of axiom �8<br />

Axiom �8 says:<br />

There is a unit scalar which acts as an identity under the exterior product.<br />

�������1, 1 �� 0 � : Α m � 1 � Α m<br />

For simplicity we do not normally display designated scalars with an underscripted zero.<br />

However, the duality transformation will be clearer if we rewrite the axiom with 1 0 in place of 1.<br />

�������1 0 ,1 0 �� 0 � : Α m � 1 0 � Α m<br />

Replace � with �, and the grades of elements and spaces by their complementary grades.<br />

�������1 n ,1 n �� n � : Α<br />

n�m � 1 n � Α<br />

n�m<br />

Replace arbitrary grades m with nÐm' (n is not an arbitrary grade).<br />

Drop the primes.<br />

�������1 n ,1 n �� n � : Α m' � 1 n � Α m'<br />

�������1 n ,1 n �� n � : Α m � 1 n � Α m<br />

In words, this says that there is a unit n-element which acts as an identity under the regressive<br />

product.<br />

The dual of axiom �10<br />

Axiom �10 says:<br />

The exterior product of elements of odd grade is anti-commutative.<br />

Α m � Β k<br />

� ��1� mk  k<br />

� Α m<br />

Replace � with �, and the grades of elements by their complementary grades.<br />

2001 4 5

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