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Grassmann Algebra

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TheComplement.nb 13<br />

Orthogonality<br />

The specific complement mapping that we impose on a <strong>Grassmann</strong> algebra will define the<br />

notion of orthogonality for that algebra. A simple element and its complement will be referred<br />

to as being orthogonal to each other. In standard linear space terminology, the space of a simple<br />

element and the space of its complement are said to be orthogonal complements of each other.<br />

This orthogonality is total. That is, every 1-element in a given simple m-element is orthogonal<br />

to every 1-element in the complement of the m-element.<br />

Visualizing the complement axiom<br />

We can use this notion of orthogonality to visualize the complement axiom geometrically.<br />

Consider the bivector x�y. Then<br />

���������<br />

x � y is orthogonal to x�y. But since<br />

���������<br />

x � y �<br />

�����<br />

x �<br />

�����<br />

y this<br />

also means that the intersection of the two (nÐ1)-spaces defined by x<br />

����� and y<br />

����� is orthogonal to<br />

x�y. We can depict it in 3-space as follows:<br />

Graphic showing three pictures<br />

1) A bivector labeled x<br />

����� with vector x orthogonal to it.<br />

2) A bivector labeled y<br />

����� with vector y orthogonal to it.<br />

3) The bivectors shown intersecting in a vector that is orthogonal to the bivector x� y.<br />

Ref JMB p60<br />

The regressive product in terms of complements<br />

All the operations in the <strong>Grassmann</strong> algebra can be expressed in terms only of the exterior<br />

product and the complement operations. It is this fact that makes the complement so important<br />

for an understanding of the algebra.<br />

In particular the regressive product (discussed in Chapter 3) and the interior product (to be<br />

discussed in the next chapter) have simple representations in terms of the exterior and<br />

complement operations.<br />

We have already introduced the complement axiom as part of the definition of the complement.<br />

Taking the complement of both sides, noting that the degree of Α m � Β k<br />

complement of a complement axiom gives:<br />

Or finally:<br />

2001 4 5<br />

���������<br />

����� �����<br />

� Αm�<br />

Βk<br />

���������<br />

Α � Β<br />

m k<br />

������������ � ��1� �m�k�n���n��m�k�n�� �Αm � Β k<br />

Α � Β � ��1�<br />

m k<br />

�m�k���m�k�n� �Α<br />

m<br />

�����<br />

������������ �����<br />

� Βk<br />

is m+kÐn, and using the<br />

5.26

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