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Grassmann Algebra

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TheRegressiveProduct.nb 9<br />

Translating this into the terminology used in this book we have:<br />

If q and r are the grades of two elements A and B, and n that of the underlying linear<br />

space, then the grade of the product [A B] is first equal to q+r if q+r is smaller than n, and<br />

second equal to q+rÐn if q+r is greater than or equal to n.<br />

Translating this further into the notation used in this book we have:<br />

�A B� � A p � B q<br />

�A B� � A p � B q<br />

p � q � n<br />

p � q � n<br />

<strong>Grassmann</strong> called the product [A B] in the first case a progressive product, and in the second<br />

case a regressive product.<br />

In the equivalence above, <strong>Grassmann</strong> has opted to define the product of two elements whose<br />

grades sum to the dimension n of the space as regressive, and thus a scalar. However, the more<br />

explicit notation that we have adopted identifies that some definition is still required for the<br />

progressive (exterior) product of two such elements.<br />

The advantage of denoting the two products differently enables us to correctly define the<br />

exterior product of two elements whose grades sum to n, as an n-element. <strong>Grassmann</strong> by his<br />

choice of notation has had to define it as a scalar. In modern terminology this is equivalent to<br />

confusing scalars with pseudo-scalars. A separate notation for the two products thus avoids this<br />

tensorially invalid confusion.<br />

We can see how then, in not being explicitly denoted, the regressive product may have become<br />

lost.<br />

3.4 The Duality Principle<br />

The dual of a dual<br />

The duality of the axiom sets for the exterior and regressive products is completed by requiring<br />

that the dual of a dual of an axiom is the axiom itself. The dual of a regressive product axiom<br />

may be obtained by applying the following algorithm:<br />

1. Replace � with �, and the grades of elements and spaces by their complementary grades.<br />

2. Replace arbitrary grades m with nÐm', k with nÐk'. Drop the primes.<br />

This differs from the algorithm for obtaining the dual of an exterior product axiom only in the<br />

replacement of � with � instead of vice versa.<br />

It is easy to see that applying this algorithm to the regressive product axioms generates the<br />

original exterior product axiom set.<br />

We can combine both transformation algorithms by restating them as:<br />

2001 4 5

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