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Grassmann Algebra

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TheInteriorProduct.nb 10<br />

����������� �����<br />

Α � Β � Αm<br />

m m<br />

����� ����� �����<br />

m��n�m�<br />

� Βm � ��1�<br />

�����<br />

�Αm � Βm<br />

� Β m<br />

�<br />

�����<br />

Α � Βm ���� Α<br />

m<br />

m<br />

From these two results we see that the order of the factors in an inner product is immaterial, that<br />

is, the inner product is symmetric.<br />

Α m ���� Β m<br />

� Β m<br />

���� Α m<br />

6.24<br />

This symmetry, is of course, a property that we would expect of an inner product. However it is<br />

interesting to remember that the major result which permits this symmetry is that the<br />

complement operation has been required to satisfy the requirement of formula 5.30, that is, that<br />

the complement of the complement of an element should be, apart from a possible sign, equal to<br />

the element itself.<br />

We have already shown in ���� 10 of the previous section that:<br />

Α m ���� Β k<br />

� ��1� �n�m���m�k� � k<br />

����� �����<br />

���� Αm<br />

Putting k = m, and using the above result on the symmetry of the inner product shows that the<br />

inner product of two elements of the same grade is also equal to the inner product of their<br />

complements.<br />

The scalar product<br />

Α m ���� Β m<br />

����� �����<br />

� Α ���� Βm<br />

m<br />

A scalar product is simply an interior or inner product of 1-elements. If x and y are 1-elements,<br />

then x����y is a scalar product.<br />

Example: Orthogonalizing a set of 1-elements<br />

Suppose we have a set of independent 1-elements Α1 , Α2 , Α3 , �, and we wish to create an<br />

orthogonal set e1 , e2 , e3 , � spanning the same space.<br />

We begin by choosing one of the elements, Α1 say, arbitrarily and setting this to be the first<br />

element e1 in the orthogonal set to be created.<br />

e1 �Α1<br />

To create a second element e2 orthogonal to e1 within the space concerned, we choose a<br />

second element of the space, Α2 say, and form the interior product.<br />

e2 � �e1 � Α2� ���� e1<br />

We can see that e2 is orthogonal to e1 by taking their interior product and using formula 6.21<br />

to see that the product is zero:<br />

2001 4 5<br />

e2 ���� e1 � ��e1 � Α2� ���� e1� ���� e1 � �e1 � Α2� ���� �e1 � e1� � 0<br />

6.25

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