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Grassmann Algebra

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ExpTheGeneralizedProduct.nb 9<br />

To expand with respect to Α we reverse the order of the generalized product to give Β����� �Α and<br />

m 3 2 4<br />

multiply by ��1� �m�� �k�� (which we note for this case to be 1) to give:<br />

B � ToInteriorProducts�Β����� �Α� 3 2 4<br />

�Β1 � Β2 � Β3 � Α1 � Α2��Α3 � Α4 � �Β1 � Β2 � Β3 � Α1 � Α3��Α2 � Α4 �<br />

�Β1 � Β2 � Β3 � Α1 � Α4��Α2 � Α3 � �Β1 � Β2 � Β3 � Α2 � Α3��Α1 � Α4 �<br />

�Β1 � Β2 � Β3 � Α2 � Α4��Α1 � Α3 � �Β1 � Β2 � Β3 � Α3 � Α4��Α1 � Α2<br />

Note that in the expansion A there are ����<br />

�<br />

3 ����<br />

(= 3) terms while in expansion B there are<br />

2 �<br />

����<br />

�<br />

4 ����<br />

(= 6)<br />

2 �<br />

terms.<br />

� Reduction to inner products<br />

At this stage the results do not look similar. Next we develop the inner product forms:<br />

A1 � ToInnerProducts�A�<br />

�Α3 � Α4 � Β2 � Β3� Α1 � Α2 � Β1 � �Α3 � Α4 � Β1 � Β3� Α1 � Α2 � Β2 �<br />

�Α3 � Α4 � Β1 � Β2� Α1 � Α2 � Β3 � �Α2 � Α4 � Β2 � Β3� Α1 � Α3 � Β1 �<br />

�Α2 � Α4 � Β1 � Β3� Α1 � Α3 � Β2 � �Α2 � Α4 � Β1 � Β2� Α1 � Α3 � Β3 �<br />

�Α2 � Α3 � Β2 � Β3� Α1 � Α4 � Β1 � �Α2 � Α3 � Β1 � Β3� Α1 � Α4 � Β2 �<br />

�Α2 � Α3 � Β1 � Β2� Α1 � Α4 � Β3 � �Α1 � Α4 � Β2 � Β3� Α2 � Α3 � Β1 �<br />

�Α1 � Α4 � Β1 � Β3� Α2 � Α3 � Β2 � �Α1 � Α4 � Β1 � Β2� Α2 � Α3 � Β3 �<br />

�Α1 � Α3 � Β2 � Β3� Α2 � Α4 � Β1 � �Α1 � Α3 � Β1 � Β3� Α2 � Α4 � Β2 �<br />

�Α1 � Α3 � Β1 � Β2� Α2 � Α4 � Β3 � �Α1 � Α2 � Β2 � Β3� Α3 � Α4 � Β1 �<br />

�Α1 � Α2 � Β1 � Β3� Α3 � Α4 � Β2 � �Α1 � Α2 � Β1 � Β2� Α3 � Α4 � Β3<br />

B1 � ToInnerProducts�B�<br />

�Α3 � Α4 � Β2 � Β3� Α1 � Α2 � Β1 � �Α3 � Α4 � Β1 � Β3� Α1 � Α2 � Β2 �<br />

�Α3 � Α4 � Β1 � Β2� Α1 � Α2 � Β3 � �Α2 � Α4 � Β2 � Β3� Α1 � Α3 � Β1 �<br />

�Α2 � Α4 � Β1 � Β3� Α1 � Α3 � Β2 � �Α2 � Α4 � Β1 � Β2� Α1 � Α3 � Β3 �<br />

�Α2 � Α3 � Β2 � Β3� Α1 � Α4 � Β1 � �Α2 � Α3 � Β1 � Β3� Α1 � Α4 � Β2 �<br />

�Α2 � Α3 � Β1 � Β2� Α1 � Α4 � Β3 � �Α1 � Α4 � Β2 � Β3� Α2 � Α3 � Β1 �<br />

�Α1 � Α4 � Β1 � Β3� Α2 � Α3 � Β2 � �Α1 � Α4 � Β1 � Β2� Α2 � Α3 � Β3 �<br />

�Α1 � Α3 � Β2 � Β3� Α2 � Α4 � Β1 � �Α1 � Α3 � Β1 � Β3� Α2 � Α4 � Β2 �<br />

�Α1 � Α3 � Β1 � Β2� Α2 � Α4 � Β3 � �Α1 � Α2 � Β2 � Β3� Α3 � Α4 � Β1 �<br />

�Α1 � Α2 � Β1 � Β3� Α3 � Α4 � Β2 � �Α1 � Α2 � Β1 � Β2� Α3 � Α4 � Β3<br />

By inspection we see that these two expressions are the same. Calculating the difference in<br />

Mathematica verifies this.<br />

A1 � B1<br />

0<br />

The identity of the forms A1 and B1 is an example of the expansion of a generalized product in<br />

terms of either factor yielding the same result.<br />

2001 4 26

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