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Grassmann Algebra

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ExploringHypercomplex<strong>Algebra</strong>.nb 5<br />

Α m ���� b � b ����Α m � b�Α m<br />

11.7<br />

From the relations 11.7 and the definition 11.1 we can determine the constraints on the<br />

m,Λ,k<br />

Σ which will accomplish this.<br />

Min�m,0�<br />

Α m ���� b � �<br />

Λ�0<br />

Min�0,m�<br />

b���� Α m � �<br />

Λ�0<br />

m,Λ,0 m,0,0 m,0,0<br />

Σ Αm ����� �b � Σ Αm � b � Σ b�Αm<br />

Λ<br />

0,Λ,m 0,0,m 0,0,m<br />

Σ b�����Λ �Α � Σ b � Αm � Σ b�Αm<br />

m<br />

m,Λ,k<br />

Hence the first constraints we impose on the Σ to ensure the properties we require<br />

for multiplication by scalars are that:<br />

The real numbers �<br />

m,0,0 0,0,m<br />

Σ � Σ � 1<br />

11.8<br />

The real numbers are a simple consequence of the relations determined above for scalar<br />

0,0,0<br />

multiplication. When the grades of both the factors are zero we have that Σ � 1.<br />

Hence:<br />

a���� b � b ����a � ab<br />

The hypercomplex product in a space of zero dimensions is therefore equivalent to the<br />

(usual) real field product of the underlying linear space. Hypercomplex numbers in a<br />

space of zero dimensions are therefore (isomorphic to) the real numbers.<br />

11.3 The Complex Numbers �<br />

Constraints on the hypercomplex signs<br />

Complex numbers may be viewed as hypercomplex numbers in a space of one<br />

dimension.<br />

In one dimension all 1-elements are of the form ae, where a is a scalar and e is the<br />

basis element.<br />

2001 4 26<br />

11.9

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