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Grassmann Algebra

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ExpTheGeneralizedProduct.nb 17<br />

1����� 0 � k<br />

�Β k<br />

When Λ greater than zero, the A form is clearly zero, and hence the B form is zero also. Thus<br />

we have the immediate result that<br />

Β k<br />

� Β 1<br />

Λ<br />

� k<br />

Λ �<br />

�<br />

j�1<br />

Β j<br />

���� Β<br />

k�Λ<br />

j<br />

Λ<br />

� Β 1<br />

k�Λ<br />

We might express this more mnemonically as<br />

� Β 1<br />

Λ<br />

Β<br />

k<br />

� Β 1<br />

k�Λ<br />

� Β 1<br />

k�Λ<br />

����  1<br />

Λ<br />

� Β 2<br />

Λ<br />

� Β 2<br />

Λ<br />

� Β 2<br />

���� Β<br />

k�Λ<br />

2<br />

Λ<br />

� 0<br />

� Β2 � �<br />

k�Λ<br />

� Β2 � Β<br />

k�Λ<br />

3 � Β<br />

Λ<br />

3 � �<br />

k�Λ<br />

� Β 2<br />

���� Β<br />

k�Λ<br />

3<br />

Λ<br />

� � � 0<br />

Generalized <strong>Grassmann</strong> products with the unit n-element<br />

10.11<br />

10.12<br />

In a development mutatis mutandis of formulae 10.11 and 10.12 we determine the consequences<br />

of one of the elements being the unit n-element 1<br />

����� .<br />

Suppose in the Generalized Product Theorem that Α is the unit n-element 1<br />

m ����� .<br />

�����<br />

1 �����Λ �Β<br />

k<br />

� k<br />

Λ �<br />

� � � 1<br />

����� ����  j<br />

j�1<br />

Λ<br />

�� j<br />

k�Λ<br />

� k<br />

Λ �<br />

� � � 1<br />

����� �  j<br />

� ����  j<br />

j�1<br />

The interior product of the unit n-element with an arbitrary element is just the complement of<br />

that element, since:<br />

�����<br />

1 ���� Βk � 1<br />

����� ����� ����������� �����<br />

� Β � 1 � Βk � Βk<br />

k<br />

Thus we see that when Λ is equal to k we have the trivial identity that:<br />

�����<br />

1 �����k �Β<br />

k<br />

�����<br />

� Β<br />

k<br />

When Λ is less than k, the B form is clearly zero, and hence the A form is zero also. Note also<br />

that the following expressions are equal, apart from a possible sign.<br />

� 1<br />

����� ����  j<br />

Λ<br />

�� j<br />

k�Λ<br />

� Β j<br />

�����<br />

j<br />

� Β<br />

Λ k�Λ<br />

�������������<br />

� Β j<br />

Λ<br />

����  j<br />

k�Λ<br />

Since if the complement of an expression is zero, then the expression itself is zero, we have<br />

2001 4 26<br />

k�Λ<br />

Λ

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