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Grassmann Algebra

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Exploring<strong>Grassmann</strong><strong>Algebra</strong>.nb 25<br />

Y � <strong>Grassmann</strong>Power�X, 3�<br />

Ξ 0 3 � 3e1 Ξ 0 2 Ξ1 � 3e2 Ξ 0 2 Ξ2 � 3 Ξ 0 2 Ξ3 e1 � e2<br />

Z � <strong>Grassmann</strong>Power�X, �3�<br />

1<br />

�������<br />

�����������������<br />

3 Ξ0 � 3e1 Ξ1<br />

Ξ4 0<br />

� 3e2 Ξ2<br />

�����������������<br />

Ξ4 0<br />

� 3 Ξ3 e1 � e2<br />

���������������������������<br />

Ξ4 0<br />

As usual, we verify with <strong>Grassmann</strong>Simplify.<br />

���Y � Z, Z � Y��<br />

�1, 1�<br />

General powers<br />

<strong>Grassmann</strong>Power will also work with general elements that are not expressed in terms of<br />

basis elements.<br />

X � 1 � x � x � y � x � y � z;<br />

�Y � <strong>Grassmann</strong>Power�X, 3�, Z� <strong>Grassmann</strong>Power�X, �3��<br />

�1 � 3x� 3x� y, 1 � 3x� 3x� y�<br />

���Y � Z, Z � Y��<br />

�1, 1�<br />

Symbolic powers<br />

We take a general <strong>Grassmann</strong> number in 2-space.<br />

�2; X� Create<strong>Grassmann</strong>Number�Ξ�<br />

Ξ0 � e1 Ξ1 � e2 Ξ2 �Ξ3 e1 � e2<br />

Y � <strong>Grassmann</strong>Power�X, n�<br />

Ξ 0 n � ne1 Ξ 0 �1�n Ξ1 � ne2 Ξ 0 �1�n Ξ2 � n Ξ 0 �1�n Ξ3 e1 � e2<br />

Z � <strong>Grassmann</strong>Power�X, �n�<br />

Ξ 0 �n � ne1 Ξ 0 �1�n Ξ1 � ne2 Ξ 0 �1�n Ξ2 � n Ξ 0 �1�n Ξ3 e1 � e2<br />

Before we verify that these are indeed inverses of each other, we need to declare the power n to<br />

be a scalar.<br />

2001 4 5<br />

DeclareExtraScalars�n�;<br />

���Y � Z, Z � Y��<br />

�1, 1�

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