14.02.2013 Views

Grassmann Algebra

Grassmann Algebra

Grassmann Algebra

SHOW MORE
SHOW LESS

Create successful ePaper yourself

Turn your PDF publications into a flip-book with our unique Google optimized e-Paper software.

Exploring<strong>Grassmann</strong><strong>Algebra</strong>.nb 32<br />

Division by a scalar<br />

Division by a scalar is just the <strong>Grassmann</strong> number divided by the scalar as expected.<br />

�X �a, X� a�<br />

� Ξ0<br />

�������<br />

�������������<br />

�<br />

a e1 Ξ1<br />

a<br />

� e2 Ξ2<br />

�������������<br />

a<br />

� Ξ3 e1 � e2<br />

����������������������� ,<br />

a<br />

Ξ0<br />

�������<br />

Division of a <strong>Grassmann</strong> number by itself<br />

Division of a <strong>Grassmann</strong> number by itself give unity.<br />

�X �X, X� X�<br />

�1, 1�<br />

Division by scalar multiples<br />

�������������<br />

�<br />

a e1 Ξ1<br />

a<br />

Division involving scalar multiples also gives the results expected.<br />

��a X��X, X� �a X��<br />

�a, 1<br />

���� �<br />

a<br />

Division by an even <strong>Grassmann</strong> number<br />

� e2 Ξ2<br />

�������������<br />

a<br />

� Ξ3 e1 � e2<br />

����������������������� �<br />

a<br />

Division by an even <strong>Grassmann</strong> number will give the same result for both division operations,<br />

since exterior multiplication by an even <strong>Grassmann</strong> number is commutative.<br />

�X ��1 � e1 � e2�, X��1 � e1 � e2��<br />

�Ξ0 � e1 Ξ1 � e2 Ξ2 � ��Ξ0 �Ξ3� e1 � e2,<br />

Ξ0 � e1 Ξ1 � e2 Ξ2 � ��Ξ0 �Ξ3� e1 � e2�<br />

� The non-uniqueness of exterior division<br />

Because of the nilpotency of the exterior product, the division of <strong>Grassmann</strong> numbers does not<br />

necessarily lead to a unique result. To take a simple case consider the division of a simple 2element<br />

x�y by one of its 1-element factors x.<br />

�x � y� �x<br />

y � xC1 � C2 x � y<br />

The quotient is returned as a linear combination of elements containing arbitrary scalar<br />

constants C1 and C2 . To see that this is indeed a left quotient, we can multiply it by the<br />

denominator from the left and see that we get the numerator.<br />

2001 4 5<br />

��x ��y � xC1 � C2 x � y��<br />

x � y

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!