entropia di entanglement in teorie invarianti conformi bidimensionali
entropia di entanglement in teorie invarianti conformi bidimensionali
entropia di entanglement in teorie invarianti conformi bidimensionali
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Appen<strong>di</strong>ce C<br />
OPE tra operatori <strong>di</strong> vertice<br />
Vogliamo provare la formula:<br />
con 〈ϕ(z, ¯z)ϕ(0)〉 = − log |z| 2 .<br />
Abbiamo:<br />
∞ (iγ1) k (iγ2) j<br />
k=0<br />
j=0<br />
=<br />
=<br />
=<br />
k!<br />
: e iγ1ϕ(z,¯z) : : e iγ2ϕ(0) : = |z| 2γ1γ2 : e iγ1ϕ(z,¯z)+iγ2ϕ(0) : , (C.1)<br />
j!<br />
∞ (iγ1) k (iγ2) j<br />
k=0<br />
j=0<br />
m<strong>in</strong>(k,j) <br />
h=0<br />
∞<br />
h=0<br />
k!<br />
j!<br />
: ϕ k (z, ¯z) : : ϕ j (0) : (C.2)<br />
m<strong>in</strong>(k,j) <br />
h=0<br />
<br />
2γ1γ2<br />
h<br />
log |z|<br />
h!<br />
<br />
2γ1γ2<br />
h<br />
log |z|<br />
h!<br />
∞<br />
k=0<br />
j=0<br />
∞<br />
k<br />
h<br />
m≡k−h=0<br />
n≡j−h=0<br />
<br />
j<br />
h! : ϕ<br />
h<br />
k−h (z, ¯z)ϕ j−h (0) : log |z| −2<br />
(iγ1) k−h (iγ2) j−h<br />
(k − h)!(j − h)!<br />
(iγ1) m (iγ2) n<br />
m!n!<br />
(C.3)<br />
: ϕ k−h (z, ¯z)ϕ(0) j−h : (C.4)<br />
: ϕ m (z, ¯z)ϕ(0) n : (C.5)<br />
= |z| 2γ1γ2 : e iγ1ϕ(z,¯z)+iγ2ϕ(0) : . (C.6)<br />
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