Proceedings Volume 2010 (format .pdf) - SimpBTH

3. RESULTS AND DISCUSSIONSFirst, we calculate the variant averages:x1= 2,30 ; x2= 1,99 ; x3= 1,68 ; x4= 1, 22132m∑xii=1The total mean is X = = 1,80 .mNow, we complete the table of variance analysis and we calculate the sum of thesquares of deviations, the degree of freedom, options to ultimately reach theexperimental value of Fisher test. We shall use formulas (1) - (8).Table 4- The table of analysis of variance for experimental dataSources ofvariationSum of square Degrees offreedomVariancesSPA = GL = 32S =A 2,48AR SPAR= 0,38 GLR= 8T SPAT= 2,1 GLT= 11AA2R0,82S = 0,042SThe experimental value of Fisher test is FAexp A= 2 = 20,5 .SRThe between-fish variance is about 20 times that between replicates for the same3,8 degrees of freedom exceeds thefish. The value table for Fisher test with ( )experimental value for a probability of 0,001. In this case, the null hypothesis isaccepted, i.e. the variant averages are not significantly different.We calculate the correlation index, by formula (9).SPAIAC ( A) = = 1,08 1.SPAWe conclude that correlation between effect of NaCN on the uptake in vitro of aparticular amino acid by intestinal preparations is very significant.We determinate now the variance of x by formula:2 2 2S = M x − M x = 3,41 − 3,24 = 0,17,( ) ( )and the standard error of a treatment mean isT2S = m0,23. Than, we computethe shortest significant ranges, i.e. S.S.R. for groups of 3 treatments and GLR= 8,as ( 0,23)4,04Q = and for 2 treatments and 8GL = as ( )RQ 0,23 = 3,26 . The