Proceedings Volume 2010 (format .pdf) - SimpBTH

difference between them is 0,78 and we compare it with the total differencebetween the largest and smallest mean, i.e. x1 − x4 = 2,30 − 1, 22 = 1,08 .Because 0,78 < 1,08 , we can say that it non-significant and we stop testing.We observe that we obtain the same conclusion as Fisher test.We apply the Tukey test to see if it reaches the same conclusion that if theFisher test. For this, we calculate the triangle of difference averages:Table 4- The table of Tukey testXi1,22 1,68 1,99 2,302,30 0,08 0,62 1,081,99 0,77 0,311,68 0,461,22In this case, the amplitude, determined by formula (10) is:2SA = R 0,38αTtab3,82 1,35m× = 3× = .We observe that the average difference values of the triangle are smaller than theamplitude, then the difference of the averages is insignificant.4. CONCLUSIONSAnalyzing experimental data and more statistical tests, we reached the sameconclusion: the diference of the variant averages are insignificant and we can saythat the variance due to differences between fish and that due to differencesbetween replicate preparations from the same fish.REFERENCES1. Parker, R.E.,(1973): Introductory Statistics for Biology, London: 67-75.2. Samboan, G., Bad M. (1986): Elements of Mathematics for biologists, Bucharest: 278-283.3. Varga M., (2009): Elements of Mathematics and Statistics with applications in biotechnologyPrintech Ed., Bucharest: 199-204.4. Varga M., (2009): Utilising the monofactorial variance analysis to determine how temperature isinfluencing the mycelia growth rate. Proceedings of the International Symposium on New Researchesin Biotechnology, Bucharest:430-437133