Online proceedings - EDA Publishing Association
Online proceedings - EDA Publishing Association
Online proceedings - EDA Publishing Association
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7-9 October 2009, Leuven, Belgium<br />
profile), if the inlet profile was reversed w.r.t. to the<br />
developed zone profile.<br />
Q w = m c (T out – T in )<br />
Q w = H (T w – T b )<br />
(5.8)<br />
(5.9)<br />
There can be different tracks to incorporate profile<br />
dependence in H in order to let it be BCI (see section 3). One<br />
of them is the flexible profile approach [7]. But in all cases, this<br />
self-contained H that would be capable of adjusting itself to<br />
meet each usage case cannot be composed of a single<br />
number, but rather a whole set of numbers, which can be<br />
arranged in a matrix that encompasses matrix H ij mentioned<br />
Where Q w is the heat power added at the wall, m is the mass<br />
flow rate while T out , T in , T w and T b are respectively outlet,<br />
inlet, wall and bulk temperatures. How many temperatures,<br />
and hence how many nodes do we need to consider The<br />
minimum is 3 because bulk temperature can be considered as<br />
a weighted average of inlet and outlet temperatures:<br />
earlier.<br />
T b = T out + (1 – ) T in (5.10)<br />
B. HTC is symmetric, while convection is not<br />
Convection is by nature a non symmetric phenomenon<br />
because upstream and downstream conditions have different<br />
effects on heat transfer. This can be seen from the governing<br />
energy equation, which reads for steady flow with uniform<br />
physical properties:<br />
2<br />
c v T<br />
T <br />
(5.6)<br />
where v is a given velocity vector field (we only consider<br />
forced convection), c and are respectively fluid density,<br />
heat capacity and thermal conductivity. Finally q v is the rate of<br />
volumetric heat generation. In case we transform this<br />
equation into a dimensionless one, we get, keeping the same<br />
symbols for dimensionless v T and q v as their dimensional<br />
counterparts:<br />
2<br />
q v<br />
q v<br />
Pe v T<br />
T <br />
(5.7)<br />
where Pe is the Peclet number Pe = v D/ (where v is a<br />
characteristic fluid velocity, D a characteristic length and <br />
thermal diffusivity). The operator acting on the unknown T<br />
contains an odd order derivative (the LHS) which means it is<br />
NOT a self similar operator. Hence, the temperature field<br />
cannot manifest the same dependence on upstream and<br />
downstream conditions (w.r.t. to the direction of v). It is wellknown<br />
that the higher is Pe the less would downstream<br />
conditions be able to affect heat transfer. For vanishingly<br />
small Pe, we recover the conduction case where both<br />
upstream and downstream conditions have the same effect on<br />
heat transfer.<br />
Modeling this non symmetric phenomenon with H is<br />
inadequate because H is the inverse of a resistance, which is a<br />
perfectly symmetric element. Let us look at the implications<br />
by considering the simplest ever problem of a straight circular<br />
duct heated at its walls according to any known profile. The<br />
complete model should involve a conservation equation (the<br />
first law) and a constitutive equation (the one involving HTC)<br />
like for instance:<br />
where, for simplicity, is considered as a known coefficient<br />
(0, 1). If we wish to confine ourselves to resistive networks<br />
(as suggests the usage of H), then we can have up to 3<br />
resistors relating the three nodes: R w_in , R w_out and R in_out .<br />
Values of these resistors are:<br />
R in_out = 1 / (m c)<br />
R w_out = 1 / ( H)<br />
R w_in = 1 / ((1 – H)<br />
(5.11.a)<br />
(5.11.b)<br />
(5.11.c)<br />
Now, if heat is added at the walls, then T out > T in , hence the<br />
model above predicts that heat should flow from outlet to<br />
inlet with an amount that is proportional to the mass flow<br />
rate! This unphysical behavior is due to the choice of a<br />
resistive based model, which does not comply with the<br />
problem nature. In case we use the matrix representation,<br />
then this matrix should be non-symmetric. More will be given<br />
on the form of this proposed matrix in section 3. Please note<br />
that this matrix should contain, among other parameters, the<br />
parameter Pe, in a form that transforms the matrix into<br />
symmetric if Pe was vanishingly small (i.e. a pure conductive,<br />
hence a pure resistive, i.e. a perfectly symmetric case).<br />
C. HTC cannot model transient effects<br />
The HTC largely depends on the boundary layer thickness,<br />
which for transient problems is time dependent. A sudden<br />
heating of the walls, of an otherwise isothermal flow, creates<br />
a time dependent thermal boundary layer of initial thickness 0<br />
all over the duct. The HTC is thus virtually infinite at start of<br />
heating. It will gradually damp to the steady state values with<br />
a time constant that depends mainly on fluid (and wall!)<br />
thermal capacity.<br />
Some researchers have proposed to use the quasi-static<br />
approximation, i.e. an instantaneous H(t) based on available<br />
steady state correlations in which we would insert<br />
©<strong>EDA</strong> <strong>Publishing</strong>/THERMINIC 2009 6<br />
ISBN: 978-2-35500-010-2