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Online proceedings - EDA Publishing Association

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7-9 October 2009, Leuven, Belgium<br />

profile), if the inlet profile was reversed w.r.t. to the<br />

developed zone profile.<br />

Q w = m c (T out – T in )<br />

Q w = H (T w – T b )<br />

(5.8)<br />

(5.9)<br />

There can be different tracks to incorporate profile<br />

dependence in H in order to let it be BCI (see section 3). One<br />

of them is the flexible profile approach [7]. But in all cases, this<br />

self-contained H that would be capable of adjusting itself to<br />

meet each usage case cannot be composed of a single<br />

number, but rather a whole set of numbers, which can be<br />

arranged in a matrix that encompasses matrix H ij mentioned<br />

Where Q w is the heat power added at the wall, m is the mass<br />

flow rate while T out , T in , T w and T b are respectively outlet,<br />

inlet, wall and bulk temperatures. How many temperatures,<br />

and hence how many nodes do we need to consider The<br />

minimum is 3 because bulk temperature can be considered as<br />

a weighted average of inlet and outlet temperatures:<br />

earlier.<br />

T b = T out + (1 – ) T in (5.10)<br />

B. HTC is symmetric, while convection is not<br />

Convection is by nature a non symmetric phenomenon<br />

because upstream and downstream conditions have different<br />

effects on heat transfer. This can be seen from the governing<br />

energy equation, which reads for steady flow with uniform<br />

physical properties:<br />

2<br />

c v T<br />

T <br />

(5.6)<br />

where v is a given velocity vector field (we only consider<br />

forced convection), c and are respectively fluid density,<br />

heat capacity and thermal conductivity. Finally q v is the rate of<br />

volumetric heat generation. In case we transform this<br />

equation into a dimensionless one, we get, keeping the same<br />

symbols for dimensionless v T and q v as their dimensional<br />

counterparts:<br />

2<br />

q v<br />

q v<br />

Pe v T<br />

T <br />

(5.7)<br />

where Pe is the Peclet number Pe = v D/ (where v is a<br />

characteristic fluid velocity, D a characteristic length and <br />

thermal diffusivity). The operator acting on the unknown T<br />

contains an odd order derivative (the LHS) which means it is<br />

NOT a self similar operator. Hence, the temperature field<br />

cannot manifest the same dependence on upstream and<br />

downstream conditions (w.r.t. to the direction of v). It is wellknown<br />

that the higher is Pe the less would downstream<br />

conditions be able to affect heat transfer. For vanishingly<br />

small Pe, we recover the conduction case where both<br />

upstream and downstream conditions have the same effect on<br />

heat transfer.<br />

Modeling this non symmetric phenomenon with H is<br />

inadequate because H is the inverse of a resistance, which is a<br />

perfectly symmetric element. Let us look at the implications<br />

by considering the simplest ever problem of a straight circular<br />

duct heated at its walls according to any known profile. The<br />

complete model should involve a conservation equation (the<br />

first law) and a constitutive equation (the one involving HTC)<br />

like for instance:<br />

where, for simplicity, is considered as a known coefficient<br />

(0, 1). If we wish to confine ourselves to resistive networks<br />

(as suggests the usage of H), then we can have up to 3<br />

resistors relating the three nodes: R w_in , R w_out and R in_out .<br />

Values of these resistors are:<br />

R in_out = 1 / (m c)<br />

R w_out = 1 / ( H)<br />

R w_in = 1 / ((1 – H)<br />

(5.11.a)<br />

(5.11.b)<br />

(5.11.c)<br />

Now, if heat is added at the walls, then T out > T in , hence the<br />

model above predicts that heat should flow from outlet to<br />

inlet with an amount that is proportional to the mass flow<br />

rate! This unphysical behavior is due to the choice of a<br />

resistive based model, which does not comply with the<br />

problem nature. In case we use the matrix representation,<br />

then this matrix should be non-symmetric. More will be given<br />

on the form of this proposed matrix in section 3. Please note<br />

that this matrix should contain, among other parameters, the<br />

parameter Pe, in a form that transforms the matrix into<br />

symmetric if Pe was vanishingly small (i.e. a pure conductive,<br />

hence a pure resistive, i.e. a perfectly symmetric case).<br />

C. HTC cannot model transient effects<br />

The HTC largely depends on the boundary layer thickness,<br />

which for transient problems is time dependent. A sudden<br />

heating of the walls, of an otherwise isothermal flow, creates<br />

a time dependent thermal boundary layer of initial thickness 0<br />

all over the duct. The HTC is thus virtually infinite at start of<br />

heating. It will gradually damp to the steady state values with<br />

a time constant that depends mainly on fluid (and wall!)<br />

thermal capacity.<br />

Some researchers have proposed to use the quasi-static<br />

approximation, i.e. an instantaneous H(t) based on available<br />

steady state correlations in which we would insert<br />

©<strong>EDA</strong> <strong>Publishing</strong>/THERMINIC 2009 6<br />

ISBN: 978-2-35500-010-2

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