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Multilin 469 Motor Management Relay ... - GE Digital Energy

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CHAPTER 5: SETTINGS<br />

This extra heating is not accounted for in the thermal limit curves supplied by the motor<br />

manufacturer, as these curves assume only positive-sequence currents from a perfectly<br />

balanced supply and motor design.<br />

The <strong>469</strong> measures the ratio of negative to positive-sequence current. The thermal model<br />

may be biased to reflect the additional heating that is caused by negative sequence<br />

current when the motor is running. This biasing is accomplished by creating an equivalent<br />

motor heating current rather than simply using average current (I per_unit). This equivalent<br />

current is calculated as shown below.<br />

where: I eq = equivalent motor heating current<br />

I per_unit = per unit current based on FLA<br />

I 2 = negative sequence current, I 1 = positive sequence current<br />

k = constant<br />

(EQ 5.3)<br />

The figure below shows recommended motor derating as a function of voltage unbalance<br />

recommended by NEMA (the National Electrical Manufacturers Association). Assuming a<br />

typical induction motor with an inrush of 6 x FLA and a negative sequence impedance of<br />

0.167, voltage unbalances of 1, 2, 3, 4, and 5% equal current unbalances of 6, 12, 18, 24,<br />

and 30% respectively. Based on this assumption, the <strong>GE</strong> <strong>Multilin</strong> curve illustrates the motor<br />

derating for different values of k entered for the UNBALANCE BIAS K FACTOR settings. Note<br />

that the curve created when k = 8 is almost identical to the NEMA derating curve.<br />

DERATING FACTOR<br />

1.05<br />

1.00<br />

0.95<br />

0.90<br />

0.85<br />

0.80<br />

0.75<br />

NEMA<br />

<strong>GE</strong> MULTILIN<br />

FIGURE 5–14: Medium <strong>Motor</strong> Derating Factor due to Unbalanced Voltage<br />

If a k value of 0 is entered, the unbalance biasing is defeated and the overload curve will<br />

time out against the measured per unit motor current. k may be calculated as:<br />

where I LR is the per-unit locked rotor current.<br />

<strong>Motor</strong> Cooling<br />

Ieq I 2 I2 per_unit 1 k --- <br />

I 1<br />

2<br />

= ⋅ + ⋅ <br />

<br />

0.70<br />

0 1 2 3 4 5<br />

PERCENT VOLTA<strong>GE</strong> UNBALANCE<br />

0.80<br />

k=6<br />

0.75<br />

0.70<br />

k=8<br />

k=10<br />

0 1 2 3 4 5<br />

808728A1.CDR<br />

(EQ 5.4)<br />

The thermal capacity used value decreases exponentially when the motor current is less<br />

than the OVERLOAD PICKUP settings. This reduction simulates motor cooling. The motor<br />

cooling time constants should be entered for both stopped and running cases. Since<br />

cooling is exponential, the time constants are one-fifth of the total time from 100%<br />

thermal capacity used to 0%. A stopped motor normally cools significantly slower than a<br />

running motor. <strong>Motor</strong> cooling is calculated as:<br />

<strong>469</strong> MOTOR MANA<strong>GE</strong>MENT RELAY – INSTRUCTION MANUAL 5–55<br />

DERATING FACTOR<br />

1.05<br />

1.00<br />

0.95<br />

0.90<br />

0.85<br />

PERCENT VOLTA<strong>GE</strong> UNBALANCE<br />

175<br />

230<br />

k = -------- (typical estimate); k = -------- (conservative estimate)<br />

2<br />

2<br />

ILR ILR k=2<br />

k=4

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