The <str<strong>on</strong>g>12th</str<strong>on</strong>g> <str<strong>on</strong>g>Internati<strong>on</strong>al</str<strong>on</strong>g> <str<strong>on</strong>g>Symposium</str<strong>on</strong>g> <strong>on</strong> <strong>District</strong> <strong>Heating</strong> <strong>and</strong> <strong>Cooling</strong>,September 5 th to September 7 th , 2010, Tallinn, Est<strong>on</strong>iaThe modified calculati<strong>on</strong> procedure is made up of thefollowing equati<strong>on</strong>s:RRR1 ,steeliD i12 steel1 D ln2 i D Doln Diinsulati<strong>on</strong>o(1)(2)(3)RUUhflow14 returnR RsR Rsembedmenti,flowi,return 2(Z R sln1 DC sembedment R Rh R Rh1 R,steel1 R,steel0) R R2 ,jacket,jacket R R(7),embedment(8),embedment(9)R,jacket12 C D ln DCinsulati<strong>on</strong>(4) i i , 50C0 ,0001T i , average 50K(10)RR,embedments12 embedment DlnC 2sD1 4 ( Z R0 s) ln2 s DC 2 sembedmentembedmentC(5)(6)TflowTreturnf r Uflow UreturnTsoil (11) 2 Ti, average Tfluid QRi R R,steel R,jacket(12)heat losses of the district heating line[W/m]18016014012010080604020without insulati<strong>on</strong> materialwith insulati<strong>on</strong> materialreducti<strong>on</strong> in %30%25%20%15%heat loss reducti<strong>on</strong>010%0 200 400 600 800 1000nominal diameter [DN]Fig. 3 Reducti<strong>on</strong> of the heat losses for DN 15 to DN 1000The average temperature of the insulati<strong>on</strong> wascalculated with following equati<strong>on</strong> <strong>and</strong> put back into(10). A VBA script was used to iterate five times.Fig. 3 shows the results of the calculati<strong>on</strong>. Theinsulati<strong>on</strong> material was taken into account with a valueof 0,33 W/m*K (λ embedment ). Around <strong>and</strong> in between theflow <strong>and</strong> the return pipe a space of 0,2 m for each pipesize was chosen (s embedment ). The depth of cover had avalue of 1 m (Z). Like in the previous example, the flowtemperature was at 120 °C <strong>and</strong> the return temperaturewas at 50 °C.Fig. 3 shows, that savings are significant lower withsmall diameters. Also the specific thickness of the PURinsulati<strong>on</strong>, which differs because of st<strong>and</strong>ardised jacketpipe diameters, has an impact.The heat losses of a DN 250 pipe are reduced from 67to 51 W/m (24%). This means, that the heat lossreducti<strong>on</strong> is 6% less compared to Fig.1.299
The <str<strong>on</strong>g>12th</str<strong>on</strong>g> <str<strong>on</strong>g>Internati<strong>on</strong>al</str<strong>on</strong>g> <str<strong>on</strong>g>Symposium</str<strong>on</strong>g> <strong>on</strong> <strong>District</strong> <strong>Heating</strong> <strong>and</strong> <strong>Cooling</strong>,September 5 th to September 7 th , 2010, Tallinn, Est<strong>on</strong>iaSince the use of an insulating backfill is more efficientwith huge diameters, a DN 700 pipe was chosen for anexample scenario. An annual average for the flow <strong>and</strong>return temperature was taken into account. For thecalculati<strong>on</strong> of the required backfill volume in theembedment, 0.2 m space in every directi<strong>on</strong> of the pipeswas estimated. It is important for the calculati<strong>on</strong> to take<strong>on</strong>ly the additi<strong>on</strong>al costs into account. That means theprice difference between cable s<strong>and</strong> <strong>and</strong> the insulati<strong>on</strong>material including the transportati<strong>on</strong> costs.A comm<strong>on</strong> value of 6% was chosen for the requiredrate of return (i).The net present value C 0 was calculated with thefollowing equati<strong>on</strong>:CTt0 I (R t) (1 i)t 1(13)The internal rate of return shown in Fig. 4 wascalculated with the IRR- functi<strong>on</strong> in Excel.Table 1 Scenario for insulati<strong>on</strong> materialParameter Value UnitLength of the districtheating line:5000 mNominal diameter: DN 700Average flowtemperature:Average returntemperature:Annual hours ofoperati<strong>on</strong>:Heat price (at the time ofthe invest):Required volume ofinsulati<strong>on</strong> material:95 °C50 °C8760 h15 €/MWh th1.85 m 3Additi<strong>on</strong>al specific costs: 16 - 17 €/m 3Required volume for thewhole line:Heat loss with use of thematerial:Heat loss without use ofthe material:9250 m 369.6 W/m90.7 W/mEnergy savings: 23.3 %Annual savings of thewhole line:924 MWh thAdditi<strong>on</strong>al investment (I): 148,000 – 157,000 €Required rate of return: 6.0 %Time of cash flow: 20 anet present value (20 years) [€]60,00050,00040,00030,00020,00016 €/m 3 17 €/m 316 €/m 3NPV10,000internal17 €/m 3rate ofreturn00.0% 1.0% 2.0% 3.0%growth rate of the heat price10.0%8.0%6.0%4.0%2.0%0.0%Fig. 4 NPV <strong>and</strong> IRR of the scenario defined in Table 1depending <strong>on</strong> the additi<strong>on</strong>al specific costs of the insulati<strong>on</strong>material.The results in Fig. 4 show, that the additi<strong>on</strong>al specificcosts should be below 17 €/m 3 in order to get a positivevalue spread, assumed that the required rate of returnis 6 %. A reducti<strong>on</strong> of specific costs of 5% (16 €/m 3 )results in an increase of the value spread by 1%. Thenet present value after 20 years rises about 10,000 €.The growth rate of the heat price is difficult to predict,but has an important influence within the given periodof 20 years. Presumably the heat price is mainlyinfluenced by emissi<strong>on</strong> trading, governmental subsidies<strong>and</strong> the development of the fossil fuel price.Other scenarios may estimate higher growth rates, butin order to get realistic results, the rate was varied from0% to 3,5%.Table 2 gives an example of materials with low heatc<strong>on</strong>ductivity that could be interesting to use as backfill.It is obvious to look for natural products, because of theprice <strong>and</strong> envir<strong>on</strong>mental regulati<strong>on</strong>s.internal rate of returnAnnual growth rate ofthe heat price:0 – 3.5 %300
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