10.02.2018 Views

archivo5

You also want an ePaper? Increase the reach of your titles

YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.

TRIGONOMETRÍA<br />

Sen<br />

⎛ π ⎞ 2<br />

⎜ x − ⎟ =<br />

⎝ 3 ⎠ 2<br />

<br />

θG<br />

π<br />

θp=<br />

4<br />

x - 3<br />

π = nπ + (-1)<br />

n<br />

π<br />

4<br />

π π<br />

x = nπ + (-1) n +<br />

4 3<br />

i) n = 2k<br />

x = 2kπ +<br />

π<br />

+<br />

π →<br />

4 3<br />

7π<br />

x = 2kπ + 12<br />

ii) n = 2k + 1<br />

π<br />

x = (2k + 1) π - +<br />

π<br />

13π<br />

→ x = 2kπ +<br />

4 3<br />

12<br />

4. 2Cos 2x – Sen3x = 2<br />

RESOLUCIÓN<br />

2(1-2Sen²x) – (3Senx – 4Sen3x) = 2<br />

4Sen²x – 4Sen²x – 3 Senx = 0<br />

Sen x (4Sen² x – 4 Senx - 3) = 0<br />

Senx (2Sen x - 3) (2Senx + 1) = 0<br />

i) Sen x = 0<br />

x = nπ<br />

ii) Senx = - 2<br />

1<br />

π<br />

x = nπ - (-1) n 6<br />

iii) Sen x = 2<br />

3 → ABSURDO<br />

5. Senx + Sen2x + Sen3x = Cosx + Cos2x + Cos3x<br />

RESOLUCIÓN<br />

2Sen2x . Cosx + Sen2x = 2 Cos2x . Cosx + Cos2x<br />

Sen2x (2Cosx + 1) = Cos2x (2Cosx + 1)<br />

Queda:<br />

Sen2x = Cos 2x<br />

Tg 2x = 1<br />

π<br />

θ p = 4<br />

θ G<br />

2x = nπ+ 4<br />

π<br />

Pero → 2Cosx + 1 = 0<br />

Cosx = - ½<br />

→ x =<br />

nπ<br />

π<br />

+<br />

2 8<br />

CUESTIONARIO DESARROLLADO

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!