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TRIGONOMETRÍA<br />

4. HALLAR: Q = arc Cos1 + arc Sen (-1) + arc Cos (-1)<br />

RESOLUCIÓN<br />

⎛ π ⎞<br />

Q = 0 + ⎜−<br />

⎟ + π =<br />

⎝ 2 ⎠<br />

π<br />

2<br />

5. HALLAR:<br />

R = Sen (arc Cos 1/3)<br />

RESOLUCIÓN<br />

α = arc Cos 1/3 → Cosα = 1/3 →<br />

Sen α = ¿??<br />

2 2<br />

Senα =<br />

3<br />

6. S = Sec² (arcTg3) + Csc² (ar Ctg 4)<br />

3<br />

α<br />

1<br />

2 2<br />

α<br />

β<br />

RESOLUCIÓN<br />

Tenemos → Tgα = 3 Ctg β = 4<br />

Piden:<br />

S = 1 + Tg²α + 1 + Ctg 2 β<br />

Sec²α + Csc²β = 27<br />

7. T = Cos (2 Arc Cos 5<br />

2 )<br />

α<br />

RESOLUCIÓN<br />

Cos α = 5<br />

2<br />

Piden T = Cos 2α = 2Cos²α - 1 T = 2<br />

8. Y = arc Sen 1/3 + arc Cos 1/3<br />

⎛<br />

⎜<br />

⎝<br />

2<br />

5<br />

⎞<br />

⎟<br />

⎠<br />

2<br />

− 21<br />

_ 1 = 25<br />

α<br />

β<br />

RESOLUCIÓN<br />

Tenemos: Senα = 3<br />

1<br />

Cos β = 3<br />

1<br />

CUESTIONARIO DESARROLLADO

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