archivo5
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TRIGONOMETRÍA<br />
4. HALLAR: Q = arc Cos1 + arc Sen (-1) + arc Cos (-1)<br />
RESOLUCIÓN<br />
⎛ π ⎞<br />
Q = 0 + ⎜−<br />
⎟ + π =<br />
⎝ 2 ⎠<br />
π<br />
2<br />
5. HALLAR:<br />
R = Sen (arc Cos 1/3)<br />
RESOLUCIÓN<br />
α = arc Cos 1/3 → Cosα = 1/3 →<br />
Sen α = ¿??<br />
2 2<br />
Senα =<br />
3<br />
6. S = Sec² (arcTg3) + Csc² (ar Ctg 4)<br />
3<br />
α<br />
1<br />
2 2<br />
α<br />
β<br />
RESOLUCIÓN<br />
Tenemos → Tgα = 3 Ctg β = 4<br />
Piden:<br />
S = 1 + Tg²α + 1 + Ctg 2 β<br />
Sec²α + Csc²β = 27<br />
7. T = Cos (2 Arc Cos 5<br />
2 )<br />
α<br />
RESOLUCIÓN<br />
Cos α = 5<br />
2<br />
Piden T = Cos 2α = 2Cos²α - 1 T = 2<br />
8. Y = arc Sen 1/3 + arc Cos 1/3<br />
⎛<br />
⎜<br />
⎝<br />
2<br />
5<br />
⎞<br />
⎟<br />
⎠<br />
2<br />
− 21<br />
_ 1 = 25<br />
α<br />
β<br />
RESOLUCIÓN<br />
Tenemos: Senα = 3<br />
1<br />
Cos β = 3<br />
1<br />
CUESTIONARIO DESARROLLADO