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du<br />

dx = 3 4<br />

dy<br />

dx = dy du<br />

du<br />

dx = 1<br />

√u − 1<br />

dy<br />

du = 1<br />

√u − 1<br />

3<br />

4 = 3<br />

4√u − 1 = 3<br />

4<br />

=<br />

3<br />

4 x − 1<br />

3<br />

4 9<br />

16 x − 1<br />

Jika y = f(x) = tanh<br />

x , maka dy<br />

dx = f'(x) = 1<br />

1 − x<br />

, |x| < 1 (5.61)<br />

Bukti<br />

y = f(x) = tanh x = 1 2 ln 1 + x<br />

1 − x , |x| < 1<br />

dy<br />

dx = 1 2 1 − x<br />

2 (1 − x) 1 + x = 1<br />

1 − x , |x| < 1 ( )<br />

Jika y = tanh<br />

Bukti<br />

y = tanh<br />

dy<br />

dx = dy<br />

u ® dy<br />

du = 1<br />

1 − u<br />

dx = 1<br />

1 − u<br />

du<br />

du<br />

Contoh 5.33<br />

u dan u = f(x) , maka dy<br />

dx = 1<br />

1 − u<br />

du<br />

dx , |u| < 1 ( )<br />

Jika y = tanh (2x − 1), tentukan dy<br />

dx<br />

Penyelesaian<br />

Misal u = 2x − 1 y = tanh u<br />

du<br />

dx = 2<br />

dy<br />

du = 1<br />

1 − u<br />

dy<br />

dx = dy du<br />

du dx = 1<br />

2<br />

(2) =<br />

1 − u 1 − (2x − 1)<br />

du<br />

dx<br />

, |u| < 1 (5.62)<br />

Jika y = f(x) = coth<br />

Bukti<br />

x , maka dy<br />

dx = f'(x) = 1 , |x| > 1 (5.63)<br />

x − 1<br />

y = f(x) = coth x = 1 2 ln x + 1<br />

x − 1 , |x| > 1<br />

dy<br />

dx = 1 −2 1 − x<br />

2 (1 − x) 1 + x = − 1<br />

1 − x = 1<br />

x − 1 , |x| > 1 ( )<br />

Jika y = coth<br />

u dan u = f(x) , maka dy<br />

dx = 1<br />

u − 1<br />

du<br />

, |u| > 1 (5.64)<br />

dx<br />

121

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