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Jaume Solà i Pujols - Departament de Filologia Catalana ...

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2.2. CHAINS<br />

A solution for the above problems can be based on Chomsky's (1986-b) theory of<br />

CHAINS, together with a version of the Exten<strong>de</strong>d Projection Principle. CHAIN can be <strong>de</strong>fined<br />

as the unification of two traditionally different syntactic concepts: A-Chains (or<strong>de</strong>red sets of A-<br />

positions linked by an antece<strong>de</strong>nt/trace <strong>de</strong>pen<strong>de</strong>ncy) and expletive/Argument <strong>de</strong>pen<strong>de</strong>ncies.<br />

CHAINS are the entities that receive θ-roles, subject to the condition they have only one Case.<br />

So both (a man, t) in 0.a) and (there, a man) in 0.b) would be instances of CHAINS:<br />

(12) a. A man came t<br />

b. There came a man<br />

In both CHAINS in 0 there is a single θ-role (namely the one assigned by to come to its<br />

internal Argument) and a single Case (namely Nominative). Since in both cases the internal<br />

Argument ends up being part of a CHAIN, we could try to exploit the i<strong>de</strong>a that it is the<br />

obligatoriness of CHAIN formation that prevents this Argument from receiving Accusative,<br />

even if Accusative is available in principle. Suppose, then, we assume the following principles,<br />

one of which is a special version of the Exten<strong>de</strong>d Projection Principle (EPP):<br />

(13) Accusative assignment is always available but optional.<br />

(14) Exten<strong>de</strong>d Projection Principle:<br />

Spec of INFL has to be a member of a CHAIN. 17<br />

17 We could alternatively <strong>de</strong>fine 0 as:<br />

(i) Spec of AGR has to head a CHAIN<br />

were it not for the case of infinitives in raising<br />

constructions, where Spec of AGR in the infinitive does not head<br />

the (maximal) CHAIN. (i) can work if we are able to <strong>de</strong>fine the<br />

sub-CHAIN hea<strong>de</strong>d by Spec of AGR as a CHAIN in an interesting<br />

way. If we simply state that any sub-CHAIN is a CHAIN, the<br />

1

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