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269 Classifying Rules with Parts<br />

square fi square þ inscribed square<br />

that I’ve been using all along. There’s one square in the left side of the rule, and there<br />

are two squares in the right side. And in fact, the rule worked perfectly in this fashion<br />

when I used it to calculate before. I applied the rule twice in this way<br />

and three times so<br />

with a redundant step that repeats the preceding shape. Moreover, the final shape in<br />

both series matches the string ( ) ( ) ( ), where each pair of parentheses indicates<br />

another square, although the palindrome ((( ))) looks to be a better fit. (Parenthesis<br />

strings are paradigmatically context free. To see this, modify the two rules in the<br />

introduction—S fi ðSÞ for h i fi hh ii and S fi SS for hifi h i h i—add the third<br />

rule S fi ð Þ, and start with the symbol or ‘‘axiom’’ S.)<br />

Other descriptions of my rule for squares, however, may be more appropriate.<br />

What if I want to use it together with a rule that finds triangles? The identity<br />

shouldn’t change anything. An identity<br />

A fi A<br />

in a generative grammar is totally useless, either because it doesn’t do anything or because<br />

A isn’t a symbol I’ve used before. But any rule I add when I calculate with shapes<br />

will automatically work as intended with any rule I’ve already used. The part relation<br />

lets me recognize triangles—or uppercase K’s and lowercase k’s—after I’ve combined<br />

squares. So it might be necessary to look at the rule<br />

under the alternative description

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