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270 II Seeing How It Works<br />

square fi four triangles<br />

The rule is still context free, but it doesn’t work. It applies once to the square<br />

and then can’t be applied again to the shape<br />

Now there are four triangles and no squares. I can patch this up by dividing triangles<br />

and squares into three sides and four sides apiece. After all, this is the way they’re normally<br />

defined. It’s what Evans did in part I, and it gives me a new way of describing the<br />

rule<br />

square with four sides fi four triangles with three sides apiece<br />

But if this is the case, then the rule must be context sensitive. Four lines are in the left<br />

side of the rule and twelve lines are in the right side. And it’s easy to see that the increase<br />

in complexity pays off when I calculate in this way<br />

where the long sides of four triangles become the four sides of a square. This is convincing<br />

proof that the rule is context sensitive—or is it? There’s still a lot more to<br />

worry about. The rule doesn’t work in the longer series<br />

It has to apply to the outside square in the second step. Under the description of the<br />

rule I’m using now, each side of the outside square is divided in two. The outside<br />

square is four lines at the start, and then eight lines one step later after adding triangles.<br />

I can try another rule that changes how squares are described, maybe one with<br />

the description<br />

eight lines fi four lines

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