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Steel Designers Manual - TheBestFriend.org

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This material is copyright - all rights reserved. Reproduced under licence from The <strong>Steel</strong> Construction Institute on 12/2/2007<br />

To buy a hardcopy version of this document call 01344 872775 or go to http://shop.steelbiz.<strong>org</strong>/<br />

<strong>Steel</strong> <strong>Designers</strong>' <strong>Manual</strong> - 6th Edition (2003)<br />

The<br />

<strong>Steel</strong> Construction<br />

Institute<br />

Silwood Park, Ascot, Berks SL5 7QN<br />

Problem 2<br />

Ae<br />

2x [ai÷[<br />

Effective Area, Ae<br />

a1 =71 x 8 =568mm2<br />

a2 =46 x 8 =368 main2<br />

5xa1 1 xa2l<br />

5xaj÷a2J j<br />

I<br />

Ae = 2 5x568<br />

x [568 1 x368<br />

[5 x 568 368 J I<br />

= 1788 mm2<br />

Subject Chapter ref.<br />

TENSION MEMBERS<br />

Worked examples 401<br />

Design code Made by ASKK Sheet no.<br />

BS 5950<br />

Checked by BD<br />

Design a double angle tie for the member AB in Problem 1. Assume the use of double<br />

angles, connected back to back through a 8 mm gusset. Assume welded connections.<br />

Code allows angle section with eccentric loading to be treated<br />

with a reduced tension capacity as given in Clause 4.6.3. 4.6.2<br />

Try 2 ¥ (75 ¥ 50 ¥ 8), connected through long leg.<br />

Area for reduced tension capacity 4.6.3.2<br />

Gross area Ag = 2 ¥ 941 = 1882 mm 2<br />

2<br />

a1= 2 ¥ ( 75 ¥ 8) = 1200 mm<br />

a2 = Ag - a1 = 1882 - 1200 = 682 mm 2<br />

Tension capacity Pt = py(Ag - 0.15a2) 4.6.3.2<br />

Pt = 355( 1882 - 0. 15 ¥ 682) = 631793 N ª 632 kN > 523 kN \ OK<br />

\ Use 2 ¥ (75 ¥ 50 ¥ 8) <strong>Steel</strong> Grade S355<br />

Note: The two angles must be connected at regular intervals. 4.6.3.2<br />

14<br />

3

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