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Handbook of Propagation Effects for Vehicular and ... - Courses

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9-8<br />

Cθ = ( θo<br />

− 7)<br />

/ 2 dB <strong>for</strong> θo<br />

< 7°<br />

<strong>Propagation</strong> <strong>Effects</strong> <strong>for</strong> <strong>Vehicular</strong> <strong>and</strong> Personal Mobile Satellite Systems<br />

(9-23)<br />

Step 5: Find the mean power <strong>of</strong> sea reflected waves Pr (in dB) relative to the direct<br />

power. This is given by<br />

Pr r ij<br />

= D + R + C (dB) (9-24)<br />

θ<br />

Step 6: Find the fading depth A (relative to the direct power) from Figure 9-1 by setting<br />

the multipath power calculated from (9-24) to the abscissa. Least square fits <strong>of</strong> the<br />

individual curves in Figure 9-1 follow the <strong>for</strong>m<br />

⎛ Pr<br />

⎞<br />

A = α exp ⎜−<br />

⎟ (dB), (9-25)<br />

⎝ β ⎠<br />

where the parameters α , β in (9-25) are tabulated in Table 9-2 <strong>for</strong> different exceedance<br />

percentages.<br />

In Figure 9-3 through Figure 9-9 are given the fading depths versus the elevation angle<br />

<strong>for</strong> antenna gains <strong>of</strong> 0, 5, 10, 15, 18, 20, <strong>and</strong> 25 dBi, respectively. These curves were<br />

derived executing the above-described steps at 1.5 GHz, assuming circular polarization.<br />

9.3.3 Example Calculation<br />

Consider the following example:<br />

f<br />

G<br />

θ<br />

o<br />

= 1.<br />

5GHz<br />

o<br />

= 10 dB<br />

= 6<br />

o<br />

Polarization<br />

= Circular<br />

(9-26)<br />

It is desired to find the signal level variation (relative to the direct power) at the 99%<br />

exceedance probability level. For circular aperture antennas, the half power beamwidth<br />

BW in (9-15) is approximately given by<br />

BW = ρ Go 180<br />

/ 20 (deg), (9-27)<br />

10<br />

where ρ is the antenna efficiency factor (between 0 <strong>and</strong> 1). Assuming a nominal value<br />

<strong>of</strong> 0.6 <strong>for</strong> ρ , BW ≈ 44°. Hence (9-15) is satisfied. We tacitly assume the conditions<br />

(9-16) <strong>and</strong> (9-17) are also satisfied. Injecting G0 = 10 dB <strong>and</strong> θ r = 1. 5,<br />

θo<br />

= 9°<br />

into (9-5),<br />

we obtain Dr = -0.29 dB. Substituting θ o = 6°<br />

into (9-23) results in Cθ = −0. 5 dB. The<br />

reflection coefficient <strong>for</strong> circular polarization is given by RCC = -6.19 dB from Table 9-1<br />

at θ o = 6°<br />

. Substituting the above values into (9-24) gives the mean power <strong>of</strong> sea<br />

reflected waves Pr = -6.98 dB. Finally, substituting α = − 24. 8271, β = −6.<br />

9088 from

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