09.01.2014 Views

Keuzecollege Hoge EnergieFysica Katholieke Universiteit ... - EHEF

Keuzecollege Hoge EnergieFysica Katholieke Universiteit ... - EHEF

Keuzecollege Hoge EnergieFysica Katholieke Universiteit ... - EHEF

SHOW MORE
SHOW LESS

Create successful ePaper yourself

Turn your PDF publications into a flip-book with our unique Google optimized e-Paper software.

2.5 Laat zien dat inderdaad alle factoren V in formule (2.41)<br />

⎛ ⎞<br />

1<br />

( dσ ----------------------------------------------------- M 2 ( 2π) 4 δ⎜<br />

) tegen elkaar<br />

4 ( p A<br />

⋅ p B<br />

) 2 2 2 ⎜<br />

p i<br />

– m AmB ∑<br />

– p A<br />

– p ⎟<br />

d 3 p i<br />

=<br />

B⎟∏<br />

----------------------<br />

⎝<br />

⎠ ( 2π) 3 2E i<br />

i = 1<br />

wegvallen. Hint: het kwadraat van de deltafunctie in<br />

kan worden geschreven als een deltafunctie<br />

maal een volume V . Laat dit ook zien.<br />

2<br />

T<br />

W fi<br />

fi<br />

= ---------- =<br />

TV<br />

N<br />

N<br />

Vd 3 p i<br />

= --------------------------------------------------- ; faseruimte<br />

;<br />

4 ( p A<br />

⋅ p B<br />

) 2 2 2<br />

– m AmB ∏----------------------<br />

( 2π) 3 V N d 3 p i<br />

= =<br />

2E i<br />

∏----------------------<br />

( 2π) 3 2E i<br />

N<br />

T fi<br />

2<br />

⎛<br />

⎞ ⎛ ⎞<br />

– i( 2π) 4 δ⎜<br />

∑<br />

p p i –<br />

A<br />

– p ⎟<br />

⎜<br />

B<br />

N<br />

⎟ A<br />

N ⎜<br />

B<br />

N ⎟<br />

∏ i<br />

M<br />

⎜ ⎟<br />

⎝<br />

⎠ ⎝ ⎠<br />

i = 1<br />

i = 1<br />

----------------------------------------------------------------------------------------------------------------<br />

TV<br />

⎛ ⎛<br />

⎞⎞ 2<br />

⎜( 2π) 4 δ⎜<br />

∑<br />

p p i –<br />

A<br />

–<br />

⎜<br />

p ⎟⎟<br />

1<br />

B<br />

--<br />

⎜<br />

⎟⎟<br />

⎝ ⎛ V⎠<br />

⎞ 2 ⎛ 1 ⎞ 2<br />

⎜ ------- ⎟<br />

∏<br />

M 2<br />

⎜<br />

⎝ ⎝<br />

⎠⎠<br />

⎝<br />

V⎟<br />

⎠<br />

i = 1<br />

i = 1<br />

= ----------------------------------------------------------------------------------------------------------------------<br />

TV<br />

N<br />

⎛ ⎛<br />

⎞⎞ TV⎜( 2π) 4 δ⎜<br />

⎜∑ p p i<br />

–<br />

A<br />

– p ⎟⎟<br />

⎜<br />

B⎟⎟<br />

⎛ 1<br />

⎝V -- ⎠<br />

⎞ 2 --<br />

1<br />

⎝ ⎛ V⎠<br />

⎞ N M 2<br />

⎝ ⎝<br />

⎠⎠<br />

i = 1<br />

= -------------------------------------------------------------------------------------------------------------- =<br />

TV<br />

1<br />

--------<br />

flux<br />

dσ<br />

V 2<br />

W fi<br />

faseruimte<br />

= -------------------------------- =<br />

flux<br />

N<br />

N<br />

N<br />

i = 1<br />

N<br />

N<br />

i = 1<br />

2<br />

N<br />

⎛<br />

⎞<br />

( 2π) 4 δ⎜<br />

∑<br />

p p i<br />

–<br />

A<br />

– p ⎟<br />

B<br />

M 2<br />

⎜<br />

⎟<br />

⎝<br />

⎠<br />

i = 1<br />

-----------------------------------------------------------------------<br />

V N + 2<br />

N<br />

i = 1<br />

⎛<br />

⎞<br />

( 2π) 4 δ⎜<br />

∑<br />

p p i –<br />

A<br />

– p ⎟<br />

⎜<br />

B⎟<br />

M 2<br />

⎝<br />

⎠<br />

i = 1<br />

V 2<br />

-----------------------------------------------------------------------<br />

V N + 2 ---------------------------------------------------V N<br />

4 ( p A<br />

⋅ p B<br />

) 2 2 2<br />

– m AmB N<br />

∏<br />

i = 1<br />

d 3 p i<br />

----------------------<br />

( 2π) 3 2E i<br />

=<br />

N<br />

⎛ ⎛<br />

⎞<br />

⎜( 2π) 4 δ⎜<br />

⎜∑ p p i – A – p ⎟<br />

⎜<br />

B⎟<br />

⎝ ⎝<br />

⎠<br />

i = 1<br />

M 2<br />

⎞<br />

⎟ 1<br />

---------------------------------------------------<br />

⎟<br />

⎠ 4 ( p A ⋅ p B ) 2 2 2<br />

– m AmB N<br />

∏<br />

i = 1<br />

d 3 p i<br />

----------------------<br />

( 2π) 3 2E i<br />

dσ e 4 ⎛<br />

2.6 Leid formule (2.48) (-------<br />

------------- 3 + 2m2 ⁄ p 2 + cos 2 θ⎞ 2 α 2 ⎛<br />

) af.<br />

dΩ 16π 2 ⎜------------------------------------------------<br />

s⎝<br />

sin 2 ⎟ ----- 3 + 2m2 ⁄ p 2 + cos 2 θ⎞ 2<br />

= = ⎜------------------------------------------------<br />

θ ⎠ s ⎝ sin 2 ⎟<br />

θ ⎠<br />

⎛<br />

⎞<br />

1<br />

dσ = ----------------------------------------------------- M 2 ( 2π) 4 δ⎜<br />

p i<br />

4 ( p A ⋅ p B ) 2 2 2<br />

– m AmB ∑<br />

– p A –<br />

⎜<br />

p ⎟<br />

B⎟<br />

⎝<br />

⎠<br />

2<br />

i = 1<br />

2<br />

∏<br />

i = 1<br />

d 3 p<br />

---------------------- i<br />

( 2π) 3 2E i<br />

144 Collegedictaat <strong>Hoge</strong> Energiefysica

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!