PDF user manual for CopperEdge 150

3ODQQLQJ0XOWLSOH+RVWVRQ+',$Although the HDIA network model allows you to place multiplehosts on a data VC and assign them at different points throughoutthe subnet—theoretically, you have 256 options, since thenumbers 0 and 255 are not reserved—you cannot choose anynumber at random. Restrictions exist.First, all consecutive addresses on a single port or IAD must belongto a range that is a power of 2. The smallest range is 1 address.The next larger can have two addresses for two hosts, thenext larger can have four, etc. A customer wanting three consecutiveaddresses for hosts must be assigned a range of fouraddresses. One will go unused. A customer wanting five addressesmust be assigned a range of eight addresses. Three willgo unused. Different ranges, of course, can exist on the samesubnet.Second, different ranges (2, 4, 8, 16, etc.) must be assigned tocertain base numbers on the subnet. For example, a range oftwo addresses must be assigned to even base numbers on thesubnet (that is, only numbers divisible by two). A range of fouraddresses must be assigned to base numbers on the subnet divisibleby four; and a range of eight addresses must be assignedto base numbers on the subnet divisible by eight.The following chart lists all of the base addresses on the subnetfor each of the different ranges.Hosts(IP Addresses)per RangeComparison of Base Addresses and Ranges of AddressesNumber ofRangesin the Subnet/32 = 1 Host 256 all integers and 0/31 = 2 Hosts 128 all even integers and 0List of Base Addressesfor the Ranges/30 = 4 Hosts 64 0, 4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48, 52, 56, 60, 64,68, 72, 76, 80, 84, 88, 92, 96, 100, 104, 108, 112, 116, 120,124, 128, 132, 136, 140, 144, 148, 152, 156, 160, 164, 168,172, 176, 180, 184, 188, 192, 196, 200, 204, 208, 212, 216,220, 224, 228, 232, 236, 240, 244, 248, 252/29 = 8 Hosts 32 0, 8, 16, 24, 32, 40, 48, 56, 64, 72, 80, 88, 96, 104, 112, 120,128, 136, 144, 152, 160, 168, 176, 184, 192, 200, 208, 216,224, 232, 240, 248/28 = 16 Hosts 16 0, 16, 32, 48, 64, 80, 96, 112, 128, 144, 160, 176, 192, 208,224, 240/27 = 32 Hosts 8 0, 32, 64, 96, 128, 160, 192, 224/26 = 64 Hosts 4 0, 64, 128, 192&RSSHU(GJH,QVWDOODWLRQDQG2SHUDWLQJ*XLGH