16.01.2013 Views

Handbook of air conditioning and refrigeration / Shan K

Handbook of air conditioning and refrigeration / Shan K

Handbook of air conditioning and refrigeration / Shan K

SHOW MORE
SHOW LESS

Create successful ePaper yourself

Turn your PDF publications into a flip-book with our unique Google optimized e-Paper software.

FIGURE 20.21 Adiabatic mixing <strong>and</strong> bypass mixing processes.<br />

<strong>and</strong> m˙ 2 / m˙ m � (20.51)<br />

hm � h1 �<br />

h2 � h1 wm � w1 � K2 w2 � w1 where K 1, K 2 � fraction <strong>of</strong> <strong>air</strong>streams 1 <strong>and</strong> 2 in the mixture.<br />

From the above-mentioned relationships<br />

1. The mixing point m must lie on the line that connects state points 1 <strong>and</strong> 2.<br />

2. The ratio <strong>of</strong> the mass flow rate <strong>of</strong> <strong>air</strong>stream 1 to the mass flow rate <strong>of</strong> the mixture is exactly<br />

equal to the ratio <strong>of</strong> segment m1-2 to segment 1-2, as shown in Fig. 20.21, that is,<br />

(20.52)<br />

Similarly, the ratio <strong>of</strong> the mass flow rate <strong>of</strong> <strong>air</strong>stream 2 to the mass flow rate <strong>of</strong> the mixture is<br />

exactly equal to the ratio <strong>of</strong> segment m1-1 to segment 1-2, that is,<br />

As the mass flow rate m˙ � V˙� , substituting into Eqs. (20.50) gives<br />

AIR SYSTEMS: BASICS AND CONSTANT-VOLUME SYSTEMS 20.51<br />

m˙ 1<br />

m˙ m<br />

m˙ 2<br />

m˙ m<br />

V˙ 1� 1h 1 � V˙ 2� 2h 2 � V˙ m� mh m<br />

V˙ 1� 1w 1 � V˙ 2� 2w 2 � V˙ m� mw m<br />

V˙ 1� 1 � V˙ 2� 2 � V˙ m� m<br />

� m1-2<br />

1-2<br />

� m1-1<br />

1-2<br />

(20.53)<br />

(20.54)

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!