16.01.2013 Views

Handbook of air conditioning and refrigeration / Shan K

Handbook of air conditioning and refrigeration / Shan K

Handbook of air conditioning and refrigeration / Shan K

SHOW MORE
SHOW LESS

Create successful ePaper yourself

Turn your PDF publications into a flip-book with our unique Google optimized e-Paper software.

where w s � humidity ratio <strong>of</strong> fan-coil supply <strong>air</strong>, lb/lb (kg/kg). As shown in Fig. 28.1b, w s � w m<br />

� w fc, <strong>and</strong> from the psychrometric chart, the humidity ratio <strong>of</strong> outdoor <strong>air</strong> w o � 0.0017 lb/lb.<br />

Therefore,<br />

So<br />

<strong>and</strong> w s � w m � w r � 0.00097 � 0.0046 � 0.00097 � 0.0036 lb/lb (0.0036 kg/kg).<br />

(28.21)<br />

12. Because at heating mode operation T r � 72°F (22.2°C), from the psychrometric chart, the<br />

relative humidity at winter design condition � r � 28 percent.<br />

13. If <strong>air</strong> leaves the preheating coil <strong>of</strong> the outdoor <strong>air</strong> AHU at T ph � 83°F <strong>and</strong> T pf � T ph � fan<br />

temperature rise � 83 � 2 � 85°F, because w o � w pf � 0.0017 lb/lb, from the psychrometric<br />

chart, <strong>air</strong> density at the fan supply outlet in the outdoor-<strong>air</strong> AHU � pf � 1/13.75 � 0.073 lb/ft 3 .<br />

The preheating coil load Q cph, in Btu/h (W), can be calculated as<br />

Q cph � 60V˙ p� pf c pa(T ph � T o)<br />

(28.22)<br />

14. If the heat loss <strong>of</strong> outdoor <strong>air</strong> supply duct is 0.5°F, T ps � 85 � 0.5 � 84.5°F, <strong>and</strong> w ps � w pf<br />

� 0.0017 lb/lb, then point ps can be determined. Draw line ps-r. Because w m � 0.0036 lb/lb<br />

(0.0036 kg/kg), point m can be plotted on the psychrometric chart. From the chart, T m � 76.2°F<br />

(24.5°C).<br />

15. The temperature <strong>of</strong> the fan-coil supply <strong>air</strong> at winter design load T s, in °F (°C), can be calculated<br />

as<br />

T s � T r �<br />

� 72 �<br />

Q rh<br />

60V˙ fc� cf c pa<br />

(28.23)<br />

As w s � w m � 0.0036 lb/lb (0.0036 kg/kg), point s can be determined, <strong>and</strong> lines r-s <strong>and</strong> m-s can<br />

be drawn. The temperature difference T s � T r � 86.9 � 72 � 14.9°F (8.3°C), which is smaller<br />

than the supply <strong>air</strong> temperature difference for warm <strong>air</strong> during heating mode 15°F (8.3°C)<br />

specified by ASHRAE h<strong>and</strong>books to prevent an excessive buoyancy effect, as discussed in<br />

Sec. 18.6.<br />

16. The <strong>air</strong> temperature at the fan outlet in the fan coil T cf � T m � 0.5 � 76.2 � 0.5 � 76.7°F.<br />

The heating coil load in the fan-coil unit Q ch, in Btu/h (W), can be calculated as<br />

Q ch � 60V˙ fc� cf c pa(T s � T cf)<br />

AIR CONDITIONING SYSTEMS: SPACE CONDITIONING SYSTEMS 28.19<br />

w r � w s<br />

w r � w o<br />

� 60 � 200 � 0.073 � 0.243(83 � 20) � 13,411 Btu/h (3929 W)<br />

9500<br />

� V˙ p<br />

V˙ fc<br />

w r � w o � w r � w s<br />

0.33<br />

� 0.0046 lb/lb (0.0046 kg/kg)<br />

60 � 2 � 300 � 0.073 � 0.243<br />

� 200<br />

600<br />

� 0.33<br />

� 0.0017 � 0.00097<br />

0.33<br />

� 72 � 14.9 � 86.9�F (30.5�C)<br />

(28.24)<br />

� 60 � 2 � 300 � 0.073 � 0.243(86.9 � 76.7) � 7152 Btu/h (2095 W)<br />

17. At winter heating mode part-load operation, the warm supply <strong>air</strong> from the fan coil, point sp,<br />

moves along the horizontal line m-sp <strong>and</strong> is supplied at a lower temperature Tsp in order to maintain<br />

the required zone temperature Trp.

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!