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Handbook of air conditioning and refrigeration / Shan K

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T Method<br />

planes 1 <strong>and</strong> 2, <strong>and</strong> the volume flow rates, <strong>and</strong> A1 <strong>and</strong> A2 the cross-sectional areas. The total<br />

pressure loss in duct section 1-2 consists <strong>of</strong> the duct friction loss �pf1-2 <strong>and</strong> the dynamic loss <strong>of</strong> the<br />

main <strong>air</strong>stream flowing through the diverging tee �p1c,s. The relationship between the total pressure<br />

at planes 1 <strong>and</strong> 2 can be expressed as<br />

(17.77)<br />

because pt � ps � pv. Ignore the difference between <strong>air</strong> densities �1 <strong>and</strong> �2. Let �pf1-2 ��pf,uL1-2. Here L1-2 represents the length <strong>of</strong> the duct section 1-2, in ft (m). If the static pressures at planes 1<br />

<strong>and</strong> 2 are equal, that is, ps1 � ps2, then<br />

(17.78)<br />

If v is expressed in fpm <strong>and</strong> �pf,u in in. WC per 100 ft, � � 0.075 lb/ft 3 , <strong>and</strong> gc � 32.2<br />

lbm�ft/lbf�s2 ��p<br />

2g<br />

f,uL1-2 �<br />

c<br />

, the mean <strong>air</strong> velocity <strong>of</strong> the sized duct section is<br />

C V˙<br />

1 V˙<br />

2<br />

pt1 � pt2 ��pf1-2 ��p1 c,s<br />

2<br />

1 c,s� v 1 1<br />

2gc In SI units,<br />

� 1(v 1 2 � v2 2 )<br />

v 2 � [(1 � C 1 c,s) v 1 2 � 1.6 � 10 5 �pf,uL 1-2] 0.5<br />

v 2 �� (1 � C 1 c,s)v 1 2 � 2�pf,uL 1-2<br />

(17.79)<br />

(17.79a)<br />

with v1 <strong>and</strong> v2 both in m/s, �pf,u in Pa/m, L1-2 in m, <strong>and</strong> � in kg/m 3 .<br />

For any duct section between cross-sectional planes n � 1 <strong>and</strong> n, if the total local loss coefficient<br />

<strong>of</strong> the duct fittings is Cn, excluding the local loss coefficient C (n�1)c,s, the mean <strong>air</strong> velocity <strong>of</strong><br />

the sized duct section is<br />

vn �� (17.80)<br />

Because vn�1, �n, Ln, <strong>and</strong> Cn are known values, by using iteration methods, vn can be determined.<br />

The dimension <strong>of</strong> the duct section <strong>and</strong> its rounded st<strong>and</strong>ard size can also be determined.<br />

The static regain method can be applied only to supply duct systems. It tends to produce a more<br />

even static pressure at the common end <strong>of</strong> each diverging tee or wye leading to the corresponding<br />

branch take<strong>of</strong>f, which is helpful to the system balance. It does not consider cost optimization. The<br />

main duct sections remote from the fan discharge <strong>of</strong>ten have larger dimensions than those in the<br />

equal-friction method. Sound level <strong>and</strong> space required should be checked against determined <strong>air</strong><br />

velocity <strong>and</strong> dimension.<br />

When one is using the static regain method to size <strong>air</strong> ducts, it is not recommended to allow only<br />

part <strong>of</strong> static regain to be used in the calculation.<br />

[(1 � C 2 5<br />

(n�1) c,s)vn�1 � 1.6 � 10 �pf,uLn] 1 � C � n<br />

0.5<br />

The T method, first introduced by Tsal et al. (1988), is an optimizing procedure to size <strong>air</strong> ducts by<br />

minimizing their life-cycle cost. It is based on the tree-staging idea <strong>and</strong> is therefore called the T<br />

method. The goal <strong>of</strong> this method is to optimize the ratio between the velocities in all sections <strong>of</strong> the<br />

duct system. The T method consists <strong>of</strong> the following procedures:<br />

1. System condensing—condensing various duct sections <strong>of</strong> a duct system into a single imaginary<br />

duct section having the same hydraulic characteristics <strong>and</strong> installation costs as the duct system<br />

�<br />

AIR SYSTEMS: AIR DUCT DESIGN 17.55<br />

� 0.5

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