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Handbook of air conditioning and refrigeration / Shan K

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20.68 CHAPTER TWENTY<br />

Winter outdoor design conditions<br />

Air temperature 32°F (0°C)<br />

Relative humidity 30 percent<br />

Winter indoor design conditions<br />

Air temperature 72°F (22.2°C)<br />

Space sensible cooling load 800,000 Btu/h (234,400 W)<br />

Space latent load 600,000 Btu/h (175,800 W)<br />

Temperature rise due to supply system heat gain 4°F (2.22°C)<br />

Temperature rise due to return system heat gain 2°F (1.11°C)<br />

Supply volume flow rate 100,000 cfm (47,190 L/s)<br />

Minimum outdoor <strong>air</strong> requirement 26,250 cfm (12,387 L/s)<br />

At winter design condition, a mixture <strong>of</strong> outdoor <strong>air</strong> <strong>and</strong> recirculating <strong>air</strong> forms the cold <strong>air</strong> supply<br />

(cooling mode operation) to <strong>of</strong>fset the space cooling load.<br />

Determine the space relative humidity at winter design conditions <strong>and</strong> the actual amount <strong>of</strong> outdoor<br />

<strong>air</strong> intake.<br />

Solution. Assume that the moist volume <strong>of</strong> the supply <strong>air</strong> vs � 13.3 ft3 /lb. From Eq. (20.65)<br />

<strong>and</strong> the given data, the humidity ratio difference between the space <strong>and</strong> supply <strong>air</strong> can be calculated<br />

as<br />

w r � w s �<br />

600,000 � 13.3<br />

�<br />

� 0.00125 lb / lb (kg / kg)<br />

60 � 100,000 � 1075<br />

From Eq. (20.31) <strong>and</strong> the given data, the supply <strong>air</strong> temperature difference Tr � Ts can be calculated<br />

as<br />

T r � T s �<br />

Q rl<br />

60V˙ s� sh fg,32<br />

Q rs<br />

60V˙ s� sc pa<br />

800,000 � 13.3<br />

�<br />

� 7.30 �F (4.1�C)<br />

60 � 100,000 � 0.243<br />

From the given data<br />

Tru � Tr � 2 � 72 � 2 � 74°F<br />

<strong>and</strong> Tm � Tr � (Tr � Ts) � 4 � 72 � 7.3 � 4 � 60.7°F (15.9°C)<br />

Because wru � wr <strong>and</strong> wm � ws, from Eq. (20.67)<br />

w r � w s<br />

w ru � w o<br />

�<br />

� T ru � T m<br />

T ru � T o<br />

74 � 60.7<br />

74 � 32<br />

� 0.317<br />

Then<br />

wr � wo �<br />

From the psychrometric chart, at a temperature <strong>of</strong> 32°F <strong>and</strong> a relative humidity <strong>of</strong> 30 percent, wo �<br />

0.0012 lb/lb, so<br />

wr � wo � 0.00394 � 0.0012 � 0.00394 � 0.00514 lb/lb<br />

wr � ws � 0.00394 lb / lb (kg / kg)<br />

0.317

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