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Handbook of air conditioning and refrigeration / Shan K

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The leakage area to the elevator shaft is<br />

A leak � 3 � 0.25 � 1000 � 0.00084 � 1.59 ft 2<br />

If the total opening at the top <strong>of</strong> the elevator shaft is 5 ft 2 , assume that only 0.5 ft 2 will be allocated<br />

for the open st<strong>air</strong>well door. For an <strong>air</strong>flow path a-b-o, if the pressure drop at the open door is negligible,<br />

the effective area is<br />

For <strong>air</strong>flow path a-c-d-o, the effective area is<br />

A e �� 1<br />

A 1 2<br />

For <strong>air</strong>flow path a-c-e-f-o, the effective area is<br />

For <strong>air</strong>flow path a-k-l-o, the effective area is<br />

AIR SYSTEMS: FAN COMBINATION AND SMOKE CONTROL 22.37<br />

FIGURE 22.9 Air discharged from an open st<strong>air</strong>well door through a<br />

combined <strong>air</strong> path to the outdoors.<br />

�� 1 1 1<br />

� � 2 2 0.52 0.52 1<br />

A e �� 1<br />

1.59<br />

Ae �� 1 �1 / 2<br />

A2� � 1 ft<br />

1 2<br />

�1 / 2 1<br />

�<br />

A2� 2<br />

A e �� 1<br />

A 1 2<br />

�� 1<br />

0.52<br />

� 1<br />

A 2 2<br />

1<br />

� 2 0.5<br />

1<br />

� 2 1<br />

�1 / 2 1<br />

�<br />

A2� 3<br />

2��1 / 2<br />

2��1 / 2<br />

2��1 / 2<br />

� 0.48 ft 2<br />

� 0.46 ft 2<br />

� 0.35 ft 2<br />

The effective area <strong>of</strong> <strong>air</strong>flow path a-g-h-o is the same as that <strong>of</strong> a-c-d-o, that is, 0.46 ft 2 ; <strong>and</strong> the<br />

effective area for a-g-i-j-o is the same as that <strong>of</strong> a-c-e-f-o, that is, 0.35 ft 2 . Therefore, the total

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