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Evolution__3rd_Edition

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124 PART 2 / <strong>Evolution</strong>ary Genetics<br />

We construct a model of gene<br />

frequencies with heterozygous<br />

advantage<br />

Sickle cell anemia illustrates the<br />

theory<br />

the frequency of a is increasing, and vice versa. Only when the chance is the same for<br />

both will the gene frequencies be stable.<br />

What is the chance that an A gene will be carried by an individual who will die without<br />

reproducing? An A gene is either (with chance q) in a heterozygote and survives or<br />

(with chance p) in an AA homozygote and has a chance s of dying. Its total chance of<br />

dying is therefore ps. An a gene similarly is either (with chance p) in a heterozygote and<br />

survives or (with chance q) in an aa homozygote and has chance t of dying: its chance of<br />

death is qt. At the equilibrium,<br />

Chance of death of an A gene = chance of death of an a gene<br />

p*s = q*t (5.10)<br />

Substitute p*s = (1 − p*)t<br />

and rearrange p* = t/(s + t) (5.11)<br />

Similarly if we substitute q = (1 − p), q* = s/(s + t). Now we have derived the equilibrial<br />

gene frequencies when both homozygotes have lower fitness than the heterozygote.<br />

The equilibrium has all three genotypes present, even though the homozygotes are<br />

inferior and are selected against. They continue to exist because it is impossible to<br />

eliminate them. Matings among heterozygotes generate homozygotes. The exact gene<br />

frequency at equilibrium depends on the relative selection against the two homozygotes.<br />

If, for instance, AA and aa have equal fitness, then s = t and p = 1 /2 at equilibrium.<br />

If AA is relatively more unfit than aa then s > t and p < 1 /2; there are fewer of the<br />

more strongly selected against genotypes.<br />

When heterozygotes are fitter than the homozygotes, therefore, natural selection<br />

will maintain a polymorphism. The result was first proved by Fisher in 1922 and<br />

independently by Haldane. We shall come later to consider in more detail why genetic<br />

variability exists in natural populations, and heterozygous advantage will be one of<br />

several controversial explanations to be tested.<br />

5.12.2 Sickle cell anemia is a polymorphism with<br />

heterozygous advantage<br />

Sickle cell anemia is the classic example of a polymorphism maintained by heterozygous<br />

advantage. It is a nearly lethal condition in humans, responsible for about<br />

100,000 deaths a year. It is caused by a genetic variant of α-hemoglobin. If we symbolize<br />

the normal hemoglobin allele by A and the sickle cell hemoglobin by S, then people<br />

who suffer from sickle cell anemia are SS. Hemoglobin S causes the red blood cells to<br />

become curved and distorted (sickle shaped); they can then block capillaries and cause<br />

severe anemia if the blocked capillary is in the brain. About 80% of SS individuals die<br />

before reproducing. With such apparently strong selection against hemoglobin S it was<br />

a puzzle why it persisted at quite high frequencies (10% or even more) in some human<br />

populations.<br />

If we compare a map of the incidence of malaria with a map of the gene frequency<br />

(Figure 5.9), we see that they are strikingly similar. Perhaps hemoglobin S provides<br />

..

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