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Evolution__3rd_Edition

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160 PART 2 / <strong>Evolution</strong>ary Genetics<br />

Protein<br />

sequence<br />

…GLY GLY LEU… …GLY ALA LEU…<br />

Rates of molecular evolution can be<br />

measured ...<br />

Species 1 Species 2<br />

Common ancestor<br />

Time<br />

(years)<br />

Figure 7.2<br />

Imagine that some region of a protein has the illustrated<br />

sequences in two species. The evolutionary change has happened<br />

somewhere within the lineage connecting the two species via their<br />

common ancestor. The simplest interpretation is that either an<br />

alanine has been substituted for a glycine in the lineage leading to<br />

species 2, or a glycine for an alanine in the lineage to species 1.<br />

Either way, the amount of evolution is one change, and it has<br />

taken place in twice the time from the species back to their<br />

common ancestor; or, one change in 2t years. In practice,<br />

particularly with DNA data, the method of maximum likelihood<br />

is used to correct for multiple hits and the possibility that the<br />

ancestor had none of the states present in the modern species<br />

(Section 15.9.3, p. 442).<br />

the approximate age of their common ancestor can be estimated from the fossil record.<br />

The rate of protein evolution can then be calculated as the number of amino acid differences<br />

between the protein of the two species divided by two times the time to their<br />

common ancestor (Figure 7.2). For example, if the species are humans and mice, their<br />

common ancestor probably lived about 80 million years ago. If we look at the sequence<br />

of a 100 amino acid protein in the two species and it differs at 16 sites, then the rate of<br />

evolution is estimated at 16/(100 × 160 × 10 6 ) ≈ 1 × 10 −9 per amino acid site per year.<br />

Much the same calculation can be made per nucleotide site for the rate of DNA<br />

evolution. But with DNA, a correction has to be made for “multiple hits.” For instance,<br />

suppose that species 1 has nucleotide A at a certain site and species 2 has G at the equivalent<br />

site. Using the reasoning of Figure 7.2, we could deduce that one change has taken<br />

place in 2t years. However, more than one change may have occurred. The common<br />

ancestor might have had nucleotide A (the same reasoning applies if it had G). In the<br />

lineage leading to species 2, A changed to G. That requires at least one change, but there<br />

may have been more. Up that lineage, A may first have evolved to T and then T to G. In<br />

the lineage leading to species 1, A may have remained unchanged all the time.<br />

Alternatively, A may have evolved into C and then C evolved to A again. We see only<br />

one difference between the A and G in the modern species 1 and 2, but more than one<br />

change may underlie it.<br />

The problem a that more than one substitution may underlie one observed difference<br />

between two species a is the problem of multiple hits. The problem is particularly<br />

acute for DNA, because DNA has only four states: the four nucleotides A, C, G, and T.<br />

Multiple evolutionary changes can easily end up leading to the same state in two<br />

species. For amino acids in proteins, there are 20 states (the 20 main amino acids) and<br />

multiple changes are less likely to result in the same state in two species. In Section<br />

15.9.3 (p. 442) we look at how to correct for multiple hits in DNA data. Analogous<br />

corrections can be made for protein data. In this chapter, we simply assume that the<br />

necessary corrections have been made in estimates of evolutionary rates.<br />

Table 7.1 gives some examples of evolutionary rate estimates, based on comparisons<br />

between humans and mice. As can be seen, different proteins evolve at different rates.<br />

Ribonuclease evolves slowly, albumin rapidly. Section 7.6 looks at why different<br />

..

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