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Evolution__3rd_Edition

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Box 7.2<br />

The Relative Rate Test<br />

The relative rate test is a method of testing whether a molecule (or,<br />

in principle, any other character) evolves at a constant rate in two<br />

independent lineages. It was first used by Sarich and Wilson in<br />

1973. Suppose we know the sequence of a protein in three species,<br />

a, b, and c, and we also know the order of phylogenetic branching<br />

of the three species (Figure B7.1). We can now infer the amounts<br />

of change in the two lines from the common ancestor of a and b to<br />

the modern species (x and y in Figure B7.1). If the protein evolved<br />

at the same rate in the two lineages, the number of amino acid<br />

changes between the common ancestor and a (x) should equal the<br />

number of changes between the common ancestor and b (y); that is,<br />

x = y. x and y can be inferred by simple simultaneous equations. We<br />

know the differences between the protein sequences in a and b (k),<br />

b and c (l), and a and c (m). Thus<br />

k = x + y<br />

l = y + z<br />

m = x + z<br />

We have three equations with three unknowns and can solve for x,<br />

y, and z. We then test whether the rates were the same by seeing<br />

whether x = y. Notice that we do not need to know the absolute<br />

date (or the identity) of the common ancestors.<br />

The relative rate test can only show that a molecule evolved at<br />

the same rate in the two lineages connecting the two modern<br />

species with their common ancestor. This does not prove that the<br />

molecule always has a constant rate; it does not, in other words,<br />

confirm the molecular clock. If identity of relative rate is shown for<br />

many pairs of species, with common ancestors of very different<br />

antiquities, that is suggestive of (and consistent with) a molecular<br />

clock, but it is not conclusive evidence. We can see why in a<br />

counterexample (Figure B7.2). Suppose that a molecule evolves<br />

at the same rate in all lineages at any one time, but that it has been<br />

gradually slowing down through evolutionary history. A pair of<br />

Figure B7.2<br />

(a) The rate of evolution of a<br />

molecule has slowed down<br />

gradually through time; but the<br />

rate of evolution is always the<br />

same in all lineages at any one<br />

time. The molecule does not<br />

evolve like a clock (which<br />

would show up as a flat graph<br />

of rate against time). (b) Then,<br />

for any pair of species, with<br />

common ancestors at any time,<br />

the amount of change will be<br />

the same in both lineages.<br />

Rate of evolution<br />

of all lineages<br />

species with a common ancestor 100 million years ago will then<br />

show rate constancy according to the relative rate test (because<br />

the molecule evolves at the same rate in all lineages at any one<br />

time); and any other species pair, for instance with a common<br />

ancestor 50 million years ago, will also show relative rate<br />

constancy. However, there is no molecular clock because the rate<br />

slows down through time. The relative rate test will not detect that<br />

the more recent species pair have a smaller absolute number of<br />

changes: absolute dates would be needed for that. The same point<br />

would apply if there were any trend in evolutionary rate with time,<br />

and it does not have to be directional. The molecule could speed up<br />

and slow down many times in evolution; but so long as the speeding<br />

up and slowing down apply to all lineages, the relative rate test will<br />

show equal rates of evolution in the two lineages. The relative rate<br />

test, therefore, cannot conclusively test the molecular clock<br />

hypothesis.<br />

(a) (b)<br />

Time<br />

z<br />

Time<br />

50<br />

100<br />

x<br />

y<br />

Species<br />

a<br />

Figure B7.1<br />

Phylogeny of three species: a, b, and c. k, l, and m are the<br />

observed number of amino acid differences between the<br />

three species. The amounts of evolution (x, y, z) in the three<br />

parts of the tree can be simply inferred, as the text explains.<br />

b<br />

c<br />

k<br />

l<br />

m<br />

p q r s<br />

r = s<br />

p = q<br />

..

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