FQ-Engel

Capítulo 5 549
P4.13
P4.14
P4.15
−91. 96 kJmol−
1
132.86 kJ mol 812.2 kJ mol 1
P4.16 a.
b.
−73. 0 kJmol−
1
−804 kJ mol−
1
P4.17 a. 428.22 kJ mol 1 ; 425.74 kJ mol 1
b. 926.98 kJ mol 1 ; 922.02 kJ mol 1
c. 498.76 kJ mol 1 ; 498.28 kJ mol 1
P4.18 Si-F 596 kJ mol 1 ; 593 kJ mol 1
Si-Cl 398 kJ mol 1 ; 396 kJ mol 1
C-F 489 kJ mol 1 ; 487 kJ mol 1
N-F 279 kJ mol 1 ; 276 kJmol 1
O-F 215 kJ mol 1 ; 213 kJ mol 1
H-F 568 kJ mol 1 ; 565 kJ mol 1
P4.19 a. 416 kJ mol 1 ; 413 kJ mol 1
b. 329 kJ mol 1 ; 329 kJ mol 1
c. 589 kJ mol 1 ; 588 kJ mol 1
P4.20
P4.21
P4.22
Uf
− 757 kJmol−
; Ho
f
516 . × 103J oC−1
− 2.86 × 103Jmol−
1, 16%
=−756 kJmol
Capítulo 5
P5.2 a.
b.
P5.3
P5.4
V
w total
=− 3.94 × 103
J
c. 0.515; 1.94 kJ
a→ b: U = H = 0; q=− w= 7.
62 × 10 3 J
b→ c: U = w=− 561 . × 10 3
J;
q=
0
H =− 935 . × 10 3 J
c→ d: U = H = 0; q=− w= 3.
68 × 10 3 J
d → a: U = w= 561 . × 10 3
J;
q=
0
H = 935 . × 10 3 J
q = 394 . × 10 3 J=−w
total
c
w
w
w
w
ab
bc
cd
da
U total
H total
0
a→ b: S = − S medio
= 8.73 J K−
1
∆S total
0
b→ c: S = − S = 0;
S
= 0
c→ d : S = − S medio
= −8.70 J K−
1
∆S total
0
= 29.6 L, V = 10.
4 L
d
=− 7.62 × 103
J
=− 5.61×
103
J
= 3.68 × 103
J
= 5.61×
103
J
1 −b1
medio
total
total
P5.5 a.
b.
d → a: S = − Smedio
= 0.
Stotal
= 0dentro del
error de redondeo; para el ciclo, S S medio
S total
0 dentro del error de redondeo
P5.6 16. 8 JK − 1
P5.7 a. ; U = 1.87 × 103
w =− 1.25 × 103
J
J ;
; S =
−
q= H
= 3.12 × 103
J 8.43 JK 1
b. w 0; ; H = 3.12 × 103
U = q= 1.87 × 103
J
J;
S = 5.06 JK−
1
c. U H 0; w q
;
S = 5.76 JK−
1 reversible
=− =− 173 . × 10 3
J
P5.8 a. S medio
=−693 . JK−
1
S total
= 150 . JK−
1 ; espontánea
b. S medio
=−4.16 JK−
1
S total
= 090 . JK−
1 ; espontánea
c. S medio
=−5.76 JK−
1
S total
= 0 ; no espontánea
P5.9 a.
b.
c.
P5.10 a.
b.
17.6 JK −1
10.6 JK −1
103 . JK−
mol
314 . JK−
mol
S transición
= 824 . JK− 1
mol−
1;
S fusión
= 25. 12 JK− 1
mol−
1
23. 49 JK −1
154. 4 JK −1
1 −1
1 −1
S =
P5.11 a. q 0; U = w=−935 J; H =− 1.31×
103
J;
S 0
b. q 0; U = w=− 748 J; H
=− 105 . × 10 3 J ;
S = 1.24 JK−
1
c. w 0; ∆U ∆H 0; 5.76 JK−
1
P5.12 a.
b.
100. 8 Jmol K
18. 94 × 10 3 Jmol−
1
P5.13 Hm
= 284 . × 103
Jmol ; Sm
= 890 . JK mol
P5.14 U = 18. 5 J; w=− 2.
73×
10 3 J
−1 −1 −1
H
= 32. 1 J; q≈ 2.
73×
103
J
S
= 910 . JK−
1
P5.15 21. 88 JK−
1
mol−
1
P5.16 a. S total
S S medio
0 0 0; no espontánea
b. S total
S S medio
1.24 J K 1 0
1.24 J K 1 ; espontánea
P5.17 a. S medio
0; S 0; S total
0; no espontánea
b. S = 27.7 JK−
1 ; ∆S medio
0;
∆S total
27.17 J K 1 ; espontánea
c. ; S medio
=−
−
S = 27.7 JK−
1 27.7 JK 1 ;
S total
0; no espontánea