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Démonstration : En multipliant la récurrence <strong>par</strong> x n , pour n ≥ k :<br />

unx n = a1un−1x n + a2un−2x n + . . . + akun−kx n<br />

En sommant sur n ≥ k :<br />

= a1xun−1x n−1 + a2x 2 un−2x n−2 + . . . + akx k un−kx n−k<br />

unx n ∞X<br />

= a1x un−1x n−1 . . . + akx k<br />

∞X<br />

= (a1x)<br />

n=k<br />

∞X<br />

n=k−1<br />

unx n + . . . +<br />

∞X<br />

n=0<br />

n=k<br />

unx n<br />

un−kx n−k<br />

En posant Pi(x) = u0 + u1x + . . . + uix i (i = 1, . . . , k − 1), on obtient :<br />

D’où on tire (vérifier) :<br />

G(x) − Pk−1(x) = a1x(G(x) − Pk−2(x)) + . . .<br />

+ ak−1x k−1 (G(x) − P0(x)) + akx k G(x).<br />

G(x) = U(x)<br />

V (x) .<br />

424

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