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Stars as Laboratories for Fundamental Physics - MPP Theory Group

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156 Chapter 4<br />

where N p<br />

± is a plane-wave nucleon state with energy E p and spin orientation<br />

± relative to k π , and κ 0 is a coupling constant.<br />

In the nonrelativistic limit the axion energy-loss rate corresponding<br />

to the decay Ñ1 → Ñ2 a is written <strong>as</strong><br />

∫<br />

Q a =<br />

d 3 k<br />

2ω(2π) 3 ω ∫ d 3 p 1<br />

(2π) 3 ∫ d 3 p 2<br />

(2π) 3 f 1(1 − f 2 )<br />

× 2π δ(E 1 − E 2 − ω) ∑<br />

|M| 2 , (4.79)<br />

spins<br />

where k is the axion momentum, p 1,2 the nucleon momenta, and f 1,2<br />

their occupation numbers. The matrix element, averaged over axion<br />

emission angles (the condensate is not isotropic!) is found to be<br />

⟨ ∑<br />

|M| 2⟩ =<br />

spins<br />

(<br />

C0 − ˜g A C 1<br />

2f a<br />

) 2<br />

4<br />

3 A2 κ 2 0<br />

× (2π) 3 [ δ 3 (∆p + k π ) + δ 3 (∆p − k π ) ] , (4.80)<br />

where ∆p = p 1 − p 2 − k. The isoscalar and isovector axion coupling<br />

constants are C 0 = 1(C 2 p + C n ) and C 1 = 1(C 2 p − C n ) in terms of their<br />

couplings to protons and neutrons. The isovector current carries a<br />

renormalized axial-vector coupling constant <strong>for</strong> which Muto, Tatsumi,<br />

and Iwamoto (1994) found ˜g A ≈ 0.43 × 1.26 = 0.54.<br />

The ph<strong>as</strong>e-space integration w<strong>as</strong> carried out by neglecting the axion<br />

momentum in δ 3 (∆p ± k π ) and taking the degenerate limit. Then,<br />

Q a = π 45<br />

( ) 2<br />

C0 − ˜g A C 1 A 2 κ 2 0m 2 NT 4<br />

, (4.81)<br />

2f a |k π |<br />

an emission rate with a relatively soft temperature dependence.<br />

For a numerical estimate Muto, Tatsumi, and Iwamoto (1994) found<br />

that in cold neutron-star matter near the critical density (about 2.1<br />

times nuclear) k π ≈ 410 MeV, the neutron and proton Fermi momenta<br />

are 410 and 150 MeV, respectively (corresponding to Y p = 0.04), and<br />

the coupling strength to the condensate is κ 0 ≈ 105 MeV. There<strong>for</strong>e,<br />

Q a = α a A 2 π2 κ 2 0 T 4<br />

45 |k π |<br />

= α a A 2 1.03×10 44 erg cm −3 s −1 T 4 9 , (4.82)<br />

where α a ≡ [2m N (C 0 − ˜g A C 1 )/2f a ] 2 /4π and T 9 ≡ T/10 9 K.

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