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LNC-M600 Leading Numerical Controller Maintenance Manual

LNC-M600 Leading Numerical Controller Maintenance Manual

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<strong>LNC</strong>-<strong>M600</strong><br />

APPENDIX A: PARAMETER ADJUSTMENT EXAMPLE<br />

3000*4<br />

CMR = = 1.2 pulses / um ,which means 1um on X axis is correspond to 1.2<br />

10000<br />

pulses that is the encoder total output signal of ball screw.<br />

Control Loop is as below:<br />

X<br />

NC<br />

Motor<br />

Ballscrew<br />

Interpolatio 1.2 K p 10/32767 200 1 1/4 1/60<br />

1/S<br />

12000<br />

Y<br />

um<br />

pulse<br />

V<br />

rpm<br />

Motor rpm<br />

ball screw rpm<br />

Ball<br />

screw<br />

rps<br />

rev<br />

pulse<br />

But, since there is no extra parameters for GR factor setting in position feedback,<br />

modification is as following:<br />

X<br />

NC<br />

Motor<br />

Ballscrew<br />

Interpolatio 1.2<br />

K p<br />

10/32767 200/4 1<br />

1/60<br />

1/S 12000<br />

Y<br />

um<br />

pulse<br />

V<br />

rpm<br />

rpm<br />

rps<br />

rev<br />

pulse<br />

Input and Output Relationship:<br />

K<br />

p<br />

⋅10<br />

32767⋅<br />

200⋅1<br />

4⋅1<br />

60⋅1<br />

S ⋅12000<br />

Y =<br />

X<br />

1+<br />

K ⋅10<br />

32767⋅<br />

200⋅1<br />

4⋅1<br />

60⋅1<br />

S ⋅12000<br />

K<br />

p<br />

⋅10<br />

32767⋅<br />

200 4⋅1<br />

60⋅1<br />

S ⋅12000<br />

3.05185K<br />

p<br />

=<br />

X =<br />

1+<br />

K ⋅10<br />

32767⋅<br />

200 4⋅1<br />

60⋅1<br />

S ⋅12000<br />

S + 3.05185K<br />

p<br />

p<br />

p<br />

X<br />

So, in this application example, parameter #0108 setting value is 200/4=50 and the<br />

K p setting value is<br />

30<br />

3.05185<br />

= 9.83 on PCC1620 motion control board.<br />

304 <strong>LNC</strong> Technology Co., Ltd.

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