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2 - Fagor Automation

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T. H5/3 Different accelerations depending on speed.<br />

Method Different accelerations depending on speed<br />

Control Linear acceleration avoiding abrupt variations in<br />

transmitted torque.<br />

Comment<br />

Emulation of the square sine function for speed by<br />

using ramps.<br />

Limited acceleration and choke. Choke = (acceleration / t).<br />

F. H5/10<br />

Acceleration and choke limit.<br />

T. H5/4 Acceleration and choke limit.<br />

Method Acceleration and choke limit.<br />

Control<br />

Progressive linear acceleration, avoiding abrupt variations<br />

of transmitted torque.<br />

Comment<br />

Approach square sine function (bell shape) for the<br />

speed.<br />

The capability demanded from the motor is determined by the following<br />

formulas:<br />

Capacity required by the motor<br />

in the constant torque area:<br />

(0 < N M < N B )<br />

Capacity required by the motor<br />

in the constant torque and constant<br />

power area:<br />

(0 < N M < N max )<br />

0<br />

speed<br />

adjust<br />

JM Inertia of the load in kg·m² as viewed from the motor shaft<br />

PN Rated power at base speed kW<br />

Nmax Maximum motor speed in rev/min.<br />

NB Motor base speed in rev/min.<br />

NM Motor speed reached after a time period t in rpm<br />

t Acceleration time until NM (in seconds) is reached<br />

P N<br />

P N<br />

2<br />

------ <br />

60 <br />

2 JM N M<br />

= ------------------- kW 1000 t<br />

We will now give several examples of calculations using a mechanical<br />

specifications and for a standard motor. The results could vary from real<br />

ones through mechanical losses, fluctuations in mains voltage, or inaccuracies<br />

of mechanical data.<br />

Example.<br />

Data:<br />

Acceleration time:<br />

Between 0 and 1500 rpm in 0.5 s. (1)<br />

Between 0 and 6000 rpm in 2.5 s. (2)<br />

Motor inertia: Jmotor = 0.13 kg·m²<br />

Motor base speed: Nb = 1500 rev/min<br />

2<br />

2 2<br />

NB<br />

Selection criteria<br />

time<br />

2<br />

------ <br />

60 <br />

2 JM N M + <br />

=<br />

-------------------------------------- kW 2000 t<br />

SELECTING CRITERIA<br />

Asynchronous spindle motor and servo drive selection 5.<br />

DDS<br />

HARDWARE<br />

Ref.1307<br />

215

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