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Problemas.estimulantes.de.probabilidad.y.estadistica

Problemas.estimulantes.de.probabilidad.y.estadistica

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c) X 1 − X 2 ∈ N(0, √ 10 2 +(−1) 2 · 10 2 ) ≡ N(0, 14.142) (se usa otra vez la fórmula (4.1), con c 1 =1y c 2 = −1).P (X 1 − X 2 < 10) = P (Z < 10−014.142 )=P (Z

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