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Problemas.estimulantes.de.probabilidad.y.estadistica

Problemas.estimulantes.de.probabilidad.y.estadistica

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Solución.La función <strong>de</strong> distribución será⎧0 si x ≤ 0⎪⎨F (x) = 0+ ∫ x0 (at2 + b)dt = 1 3 ax3 + bx si 0

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