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Libro Mecánica de Materiales (Prácticas y Exámenes UPC)

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P 1<br />

P 1<br />

P 2<br />

s<br />

<br />

De don<strong>de</strong>:<br />

A<strong>de</strong>más, se sabe que:<br />

2P1 10<br />

3<br />

P2<br />

400.<br />

…………………… (a)<br />

P s <br />

1 P 2<br />

P1<br />

L P2L<br />

s <br />

EA EA<br />

EAs<br />

P<br />

…………………… (b)<br />

L<br />

P1 2<br />

<br />

Reemplazamos (b) en (a) y obtenemos:<br />

Luego:<br />

P2L<br />

s 10<br />

EA<br />

3<br />

2EAs<br />

2P<br />

<br />

L<br />

3P<br />

c) Calculamos el valor <strong>de</strong> P<br />

1<br />

3<br />

2<br />

P2<br />

400. 10<br />

2<br />

400.10<br />

3<br />

P 2<br />

43,33kN<br />

3<br />

43,33.10 .1<br />

<br />

9<br />

45.10 .3000.10<br />

9<br />

2.45.10 .3000.10<br />

<br />

1<br />

6<br />

1,321.10<br />

3<br />

6<br />

.10<br />

3<br />

m 1,321mm<br />

9<br />

6<br />

3<br />

EAs<br />

3 45.10 .3000.10 .10<br />

P1 P2<br />

43,33.10 <br />

178,33kN<br />

L<br />

1<br />

Luego:<br />

2 2 2<br />

P1<br />

L P2<br />

L P1<br />

L <br />

U P<br />

2EA 2EA 2EA<br />

<br />

<br />

U 242,52J<br />

2<br />

1<br />

2<br />

P <br />

2<br />

<br />

2<br />

<br />

<br />

L<br />

EA<br />

<br />

<br />

178,33<br />

<br />

2<br />

43,33<br />

<br />

2<br />

2<br />

<br />

6 1<br />

.10<br />

.<br />

9<br />

45.10 .3000.10<br />

6<br />

36

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