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自动控制原理第三章时域分析法N9872% 误差带5% 误差带65432100 0.2 0.4 0.6 0.8 1振荡次数 N 与的关系
自动控制原理第三章时域分析法例设位置随动系统的开环传递函数Gs ( ) 5K当给定位置为单位阶跃时 , 试计算放大器增益 K A=200 时 , 输出位置响应特性的性能指标 : 峰值时间 t p、调节时间 t s和超调量 % 。如果将放大器增益增大到K A=1500 或减小到 K A=13.5, 那么对响应的动态性能有何影响 ?Ass ( 34.5)
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自动控制原理第一章
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自动控制原理三、反
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自动控制原理第二章
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自动控制原理5. 正弦
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自动控制原理三、拉
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自动控制原理二、对
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自动控制原理三、理
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自动控制原理本章小
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自动控制原理第三章
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自动控制原理2. 速度
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自动控制原理求出 EN
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自动控制原理第四章
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自动控制原理证明 :
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自动控制原理会合角
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自动控制原理(7) 分离
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自动控制原理解之 ,
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自动控制原理例第四
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自动控制原理式中第
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自动控制原理二、主
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自动控制原理一阶系
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自动控制原理常规根
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自动控制原理开环极
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自动控制原理第五章
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自动控制原理11+ω T2 2
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自动控制原理动态数
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自动控制原理三、微
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自动控制原理五、一
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自动控制原理5.5 闭环
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自动控制原理如果 A(ω
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自动控制原理第六章
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自动控制原理例第六
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自动控制原理第七章
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自动控制原理二、数
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自动控制原理7.2 信号
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自动控制原理系数第
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自动控制原理三、Z 变
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自动控制原理例试求
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自动控制原理7. 终值
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自动控制原理查表 7-1
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自动控制原理也可由
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自动控制原理一、稳
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自动控制原理次要带j
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自动控制原理由变换
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自动控制原理四、稳
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自动控制原理第八章
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自动控制原理2. 状态
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自动控制原理7. 状态
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自动控制原理1. 能控
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自动控制原理2. 能观
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自动控制原理二、传
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自动控制原理本章小
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