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自 动 控 制 原 理*第 七 章 采 样 数 据 控 制 系 统 分 析如 果 E * (jω) 没 有 右 半 平 面 的 极 点 , 则 令s = jω , 得 到+∞* 1E (j ω) = E⎡j( ω+kωs) ⎤T⎣ ⎦∑T k =−∞(a) 连 续 信 号 e(t) 的 频 谱|E(jω)|-ωω max O ω max ω

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