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自 动 控 制 原 理第 七 章 采 样 数 据 控 制 系 统 分 析证 明 :∞(1)Z[( et− nT )] = ∑ e ( kT −nT ) z −k=0∞= ∑ −k=0∞k−−z e[( k n) T]z z= ∑ −n k zz e[( k n) T]z−n −( k−n)k=0∞−n∑−jz e (j T ) z ( j k n)j=−n= ∑= −