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自动控制原理例试求 β k cosω t 的 Z 变换。解 : 由 Z 变换表ZZ[cos ωt]=k[ βcos ωt]=第七章采样数据控制系统分析zz( −cos ωT)2z − 2zcosωT+ 1z z( − cos ωT)β βz 2 z( ) − 2 cosωT+ 1ββ−11−βzcosωT=−1 2 −21− 2β z cosωT + β z
自动控制原理第七章采样数据控制系统分析6. 初值定理若已知 e(t) 的 Z 变换为 E(z), 并有lim Ez( )z→∞存在 , 则*lim[ e ( t )] =lim E ( z)t→0z→∞证明 : 因为Ez( ) =∑ekTz( )所以∞k=0−1 −2= e (0) + e ( T ) z + e (2 T )z +⋅⋅⋅*lim E( z) = e(0) = lim e ( t)z→∞t→0−k
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自动控制原理第一章
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自动控制原理三、反
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自动控制原理第二章
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自动控制原理5. 正弦
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自动控制原理三、拉
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自动控制原理三、理
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自动控制原理本章小
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自动控制原理第三章
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自动控制原理2. 速度
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自动控制原理则 Th( t) 1
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自动控制原理闭环传
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自动控制原理所以cosdt
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自动控制原理5. 振荡
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自动控制原理2. 测速
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自动控制原理各阶赫
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自动控制原理3. 劳思 (
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自动控制原理(2) 劳思
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自动控制原理由稳定
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自动控制原理求出 EN
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自动控制原理第四章
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自动控制原理证明 :
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自动控制原理会合角
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自动控制原理(7) 分离
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自动控制原理解之 ,
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自动控制原理例第四
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自动控制原理式中第
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自动控制原理二、主
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自动控制原理一阶系
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自动控制原理常规根
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自动控制原理开环极
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自动控制原理第五章
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自动控制原理11+ω T2 2
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自动控制原理动态数
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自动控制原理三、微
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自动控制原理五、一
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自动控制原理5.5 闭环
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自动控制原理如果 A(ω
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自动控制原理第六章
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自动控制原理第七章
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自动控制原理一、稳
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自动控制原理次要带j
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自动控制原理由变换
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自动控制原理四、稳
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自动控制原理2. 状态
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自动控制原理7. 状态
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